Angles of a triangle always add up to 180 degrees. The given angles (90, 90, 20 degrees) give a total of 200 degrees, hence they cannot form a triangle.
In order for three angles to form a triangle, they must satisfy the triangle inequality theorem, which states that the sum of the measures of any two angles in a triangle must be greater than the measure of the third angle.
In this case, you have angles measuring 90 degrees, 90 degrees, and 20 degrees. Let's apply the theorem:
1. Angle 1: 90 degrees
2. Angle 2: 90 degrees
3. Angle 3: 20 degrees
Now, let's check if these angles satisfy the triangle inequality theorem:
- Angle 1 + Angle 2 = 90 degrees + 90 degrees = 180 degrees
- Angle 3 = 20 degrees
According to the theorem, the sum of any two angles must be greater than the measure of the third angle. However, in this case, the sum of Angle 1 and Angle 2 (180 degrees) is not greater than Angle 3 (20 degrees). Therefore, these angles do not satisfy the triangle inequality theorem.
So, the answer is "no," 90 degrees, 90 degrees, and 20 degrees cannot form a triangle because they do not satisfy the triangle inequality theorem.
Learn more about Angles of a triangle
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Answer:
no. never.
Step-by-step explanation:
total internal angles of a triangle sum to 180. 90 + 90 is 180 so no, you cannot have a triangle with sides 90 90 and 20. it is possiblw to have 90 45 and 45 though
Hi!
The answer is exactly those 20% of the dress, so 20% * 60$ = 0,2 * 60 = 12$.
Hope this helps!
The problem involves calculating a percentage saving on a purchase. Angela is buying a dress originally priced at $60 but has a 20% discount, which means she is saving $12 on her purchase.
Angela is looking to buy a dress that has a 20% discount. The original price of the dress is $60. To calculate how much Angela will save, we first need to find out what 20% of $60 is. To do this, we perform the following steps:
Therefore, "Angela will be saving $12 on her dress purchase".
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y=x^2-4x+4
b. horizontal bar graph.
c. line graph.
d. moving bar chart.
When putting in the function into desmos, you must put it as (ex: y=30000*(1.04)^x)
Desmos does not recognize other letters than x and y.