Answer: 43 minutes and 14 seconds.
Explanation:
The speed of light in a vacuum is approximately 186,282 miles per second (299,792 kilometers per second). To find the time it takes for light to travel from the Sun to Jupiter, divide the distance by the speed of light:
Time = (Distance from Sun to Jupiter) / (Speed of Light)
Time = (5.2 AU * 93 million miles/AU) / (186,282 miles/second)
Now, you can calculate the time in seconds and convert it to minutes:
Time = [(5.2 * 93 million miles) / (186,282 miles/second)] * (1 minute / 60 seconds)
Time ≈ [(483.6 million miles) / (186,282 miles/second)] * (1 minute / 60 seconds)
Time ≈ (2594.16 seconds) * (1 minute / 60 seconds)
Time ≈ 43.236 minutes
So, it takes approximately 43.236 minutes for light from the Sun to reach Jupiter, which is about 43 minutes and 14 seconds.
The energy equation, E=12mvx2+12kx2=12kA2, is a useful alternative relationship between velocity and position, especially when energy quantities are also required. If the problem involves a relationship among position, velocity, and acceleration without reference to time, it is usually easier to use the equation for simple harmonic motion, ax=d2xdt2=−kmx (from Newton’s second law) or the energy equation above (from energy conservation) than to use the general expressions for x, vx, and ax as functions of time. Because the energy equation involves x2 and vx2, it cannot tell you the sign of x or of vx; you have to infer the sign from the situation. For instance, if the body is moving from the equilibrium position toward the point of greatest positive displacement, then x is positive and vx is positive.
IDENTIFY the relevant concepts
Energy quantities are required in this problem, therefore it is appropriate to use the energy equation for simple harmonic motion.
SET UP the problem using the following steps
Part A
The following is a list of quantities that describe specific properties of the toy. Identify which of these quantities are known in this problem.
Select all that apply.
Select all that apply.
maximum velocity vmax
amplitude A
force constant k
mass m
total energy E
potential energy U at x
kinetic energy K at x
position x from equilibrium
Part B
What is the kinetic energy of the object on the spring when the spring is compressed 5.1 cm from its equilibrium position?
Part C
What is the potential energy U of the toy when the spring is compressed 5.1 cm from its equilibrium position?
Answer:
Part A
Mass = 50g
Vmax = 3.2m/s
Amplitude= 6cm
Position x from the equilibrium= 5.1cm
Part B
Kinetic energy = 0.185J
Part C
Potential energy = 0.185J
Explanation:
Kinetic energy = 1/2mv×2
Vmax = wa
w = angular velocity= 53.33rad/s
Kinetic energy = 1/2mv^2×r^2 = 0.185J
Part c
Total energy = 1/2m×Vmax^2= 0.256J
1/2KA^2= 0.256J
K= 142.22N/m (force constant)
Potential energy = 1/2kx^2
=1/2×142.22×0.051^2
= 0.185J
To find the kinetic energy of the toy, we need to use the energy equation for simple harmonic motion and the relationship between velocity and position. We can then substitute the known values to calculate the kinetic energy.
In this problem, we are given the amplitude (A) of the oscillation and the maximum velocity (vmax) achieved by the toy. We need to find the kinetic energy (K) of the toy when the spring is compressed 5.1 cm from its equilibrium position.
To solve for the kinetic energy, we can use the energy equation for simple harmonic motion: K = 1/2mvx2, where m is the mass of the object and vx is the velocity of the object at position x. The mass of the object is given as 50 g, which is equal to 0.05 kg.
Since we know the maximum velocity (vmax = 3.2 m/s), we can use the relationship between velocity and position in simple harmonic motion to find the velocity (vx) at a displacement of 5.1 cm from the equilibrium position. The velocity and position in simple harmonic motion are related by vx = ±ω√(A2 - x2), where ω is the angular frequency of the motion.
Substituting the known values into the equations, we can calculate the kinetic energy of the toy.
#SPJ3
Answer:
o m
Explanation:
The net displacement is 0 because it returns to its original position. The final position and initial position are the same, so displacement is 0.
B. 273 K
C. 560 K
D. 140 K
Answer:
The correct answer is option A.
Explanation:
Initial volume of the gas
Initial temperature of gas
Final volume of the gas
Final temperature of the gas =
Applying Charles' Law:
The temperature of the gas when volume of the gas is 20.0 L is 160 K.Hence, the correct answer is option A.
Answer:
65
Explanation:
50+3*5
Answer:
The total velocity of the ball will be 14.14 m/s.
Explanation:
Horizontal Velocity component = 10 m/s
Vertical Velocity component = -10 m/s
Total velocity of the ball will be found from the following equation:
(Total velocity) ^2 = (Horizontal Velocity) ^2 + (Vertical Velocity) ^2
Total Velocity ^2 = 10^2 + (-10)^2
Total Velocity^2 = 100 + 100
Total Velocity =
Total Velocity = 14.14 m/s
a. True
b. False
This statement is TRUE.