PHYSICS HIGH SCHOOL

5. You head downstream on a river in an outboard.The current is flowing at a rate of 1.50 m/s. After
30.0 min, you find that you have traveled 24.3 km.
How long will it take you to travel back upstream to
your original point of departure?

Answers

Answer 1
Answer:

Answer:

hope this helps you're welcome
Answer 2
Answer:

Final answer:

The time it will take to travel back upstream to your original point of departure is approximately 38.6 minutes, as determined by calculating the boat's speed against and with the river current.

Explanation:

This question involves understanding the concepts of velocity, time, and distance in physics. It relates to a situation where you are traveling downstream on a river with a certain current and later traveling back upstream against the current.

Firstly, we need to understand that the speed of the boat when it is moving downstream is its own speed plus the speed of the current. Given that you covered 24.3 km in 30 minutes (or 0.5 hours), we can calculate the boat's downstream speed as 24.3 km / 0.5 hours = 48.6 km/h.

The speed of the current is given as 1.50 m/s, which is approximately 5.4 km/h. So, the boat's own speed would be 48.6 km/h (downstream speed) - 5.4 km/h (current speed) = 43.2 km/h.

When heading back upstream, the boat's effective speed would be its own speed minus the speed of the current, which is 43.2 km/h - 5.4 km/h = 37.8 km/h. Now, to find out the time it would take to travel back upstream to the original point, we divide the total distance by the boat's effective speed, i.e., 24.3 km / 37.8 km/h = approximately 0.643 hours or around 38.6 minutes.

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Light travels faster in glass than it does in a vacuum. Please select the best answer from the choices provided T F

Answers

From among the choices provided, the better answer is ' F ',
the initial letter of the word ' False '. 

Light does not travel faster in glass than it does in vacuum. 
Light travels slower in glass than it does in vacuum. 

As a matter of fact, light travels slower in anything than it does
in vacuum.
False.

Light travels faster in vacuum than in glass.

Within a single use of the scientific method, which of the following steps can only be performed afterdata is collected?
A. Controls and variables are chosen.
B. The initial experiment is designed.
C. The initial hypothesis is formed.
D. Conclusions are drawn.

Answers

Within a single use of the scientific method, the step which would be performed after we collect data, would be the drawing of a conclusion out of the answers that you've presented - D.

It is usually the case that you first have to analyze the data after you've gather it and then you base your conclusions on it. This isn't, however, always the case. 

What is the gravitational force acting on a 70.0 kg object standing on the earth's surface ?

Answers

g( gravitational acceleration)=-9.81 m/s^2
m(mass) = 70.0 kg

According to Newton's second law of motion:

"F=ma"

Force is equal mass per acceleration therefore

W=mg
This is because weigth is the force of gravity acting in a body and "a" is replaced by "g" because "g"
is gravitational acceleration

Therefore:

W= mg
W= (70.0 kg) (-9.81m/s^2)
W= -686.7 N

* The "N" means newton which is (kg* m/s^2)

Final answer:

The gravitational force acting on a 70.0 kg object on Earth is calculated using the formula w=mg and is equal to 686 N.

Explanation:

The gravitational force acting on a 70.0 kg object standing on the earth's surface can be calculated using the formula for weight (which is essentially the gravitational force on the object): w = mg, where m is the mass of the object and g is the acceleration due to gravity. On Earth, g is approximately 9.8 m/s².

Therefore, the gravitational force (weight) acting on this object can be calculated as follows: w = mg = (70.0 kg)(9.8 m/s²) = 686 N. Thus, the gravitational force on this 70.0 kg object standing on the earth's surface is 686 Newtons. It's important to understand that this force will vary if the object is moved to a location where g is different, like on the moon.

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a ball is dropped from rest at a height of 80 m above the ground. what is the speed just as it hits the ground?

Answers

Δx=Vi(t)+.5at²
Δx=80
a=9.8
Vi=0 since its from rest, the initial velocity is 0.
80=0+.5(9.8)t²
t=16.33
You can use one of the big five equations: Vf=Vi+at
Vf=0+9.8(16.33)
Vf=160.034 m/s

Which one of the following accurately describes the force of gravity

Answers

The force of gravity, also called gravitational force, is the force exerted by the gravity of one object to another object near it. This is dependent on factors like mass of the two objects measured between their centers. 

A train is accelerating at a rate of 2 km/hr/s.  If its initial velocity is 20 km/hr, what is its velocity after 30 seconds?

Answers

"2 km/hr/s" means that in each second, its engines can increase its speed by 2 km/hr.

If it keeps doing that for 30 seconds, its speed has increased by 60 km/hr.

On top of the initial speed of 20 km/hr, that's 80 km/hr at the end of the 30 seconds.

This whole discussion is of speed, not velocity. Surely, in high school physics,
you've learned the difference by now. There's no information in the question that
says anything about the train's direction, and it was wrong to mention velocity in
the question.  This whole thing could have been taking place on a curved section
of track. If that were the case, it would have taken a team of ace engineers, cranking
their Curtas, to describe what was happening to the velocity.  Better to just stick with
speed.
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