(2) decreased temperature and decreased pressure
(3) increased temperature and increased pressure
(4) increased temperature and decreased pressure
The changes in temperature and pressure will cause this sample to behave more like an ideal gas by increased temperature and decreased pressure. Hence option 4 is correct.
Ideal gas is defined as a gas that physically behaves in accordance with the ideal, or general, gas law, which is a certain idealized relationship between pressure, volume, and temperature. The ideal gas law can be used to calculate the volume of gases that are produced or used. The ideal-gas equation is frequently used in chemical equations to convert between volumes and molar values.
Ideal gases are those that have little volume and no intermolecular forces. Real gas must have intermolecular attractions and volume in order to exist. At low pressure and high temperature, a genuine gas will act as it should.
Thus, the changes in temperature and pressure will cause this sample to behave more like an ideal gas by increased temperature and decreased pressure. Hence option 4 is correct.
To learn more about ideal gas, refer to the link below:
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Answer : The correct option is, (4) increased temperature and decreased pressure
Explanation :
The conditions for ideal gas are, it has no intermolecular attractions and have negligible volume.
The ideal gas equation is,
The conditions for real gas are, it has intermolecular attractions and have volume.
The real gas equation is,
A real gas behave ideally at high temperature and low pressure conditions.
From the given options, option (4) increased temperature and decreased pressure is the correct option.
Hence, increased temperature and decreased pressure this sample to behave more like an ideal gas.
b. a phosphate group.
c. a sugar group.
d. pyrimidines.
Answer:
6.40x10²⁵ hydrogen atoms
Explanation:
The solution contains:
We need to calculate the total of hydrogen atoms (H) in the solution.
Lets now calculate the number of hydrogen atoms in the solution:
total H atoms = (H atoms in water molecules) + (H atoms in ammonia molecules)
total H atoms = (2 x 1.80x10²⁵) + (4 x 7.00x10²⁴) =
total H atoms = 3.60x10²⁵ + 2.80x10²⁵ = 6.40x10²⁵
Explanation:
According to reaction, 2 atoms of aluminum gas reacts with 3 molecules of chlorine gas.
Then 20 atoms of aluminum will react with :
of chlorine
Aluminum is a limiting reagent.
Molecules of chlorine left unreacted: 45 - 30 molecules = 15 molecules
Then 15 molecules of chlorine gas will react with :
of aluminum
10 more atoms of aluminum will required to use up all chlorine.