Pls help with this for 30points

Answers

Answer 1

Answer:

2.11. Tariff is the cost or charge for a service.

2.2.2. The cost of refilling the pool with 15kl of water is R285.90.

2.2.3. The VAT inclusive cost for 15kl is R328.79.

2.11. Tariff is the cost or charge for a particular service or resource. It can be thought of as a rate or price that is applied to a specific quantity or volume of the resource being used.

2.2.2. To calculate the cost of refilling the pool, we need to determine the amount of water required and then multiply it by the appropriate tariff rate.

In this case, 15 kilolitres of water needs to be refilled, and based on the provided tariffs, the cost would be: 15 kl x R19.06/kl = R285.90.

2.2.3. To calculate the VAT inclusive amount for using 15 kl, we need to include the value-added tax (VAT) to the cost. VAT is calculated as a percentage of the initial cost.

Assuming a VAT rate of 15%, the VAT inclusive cost would be: R285.90 + (15/100 x R285.90) = R328.79.

For more such questions on Tariff, click on:

brainly.com/question/33033796

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Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.

Answers

Answer:

Option (a) is correct.

The solution is (1, -1 , -4)

Step-by-step explanation:

Given:

A system of equation having 3 equations,

$2x+y+z=-3\n\n 3x-5y+3z=-4\n\n 5x-y+2z=-2$

We have to solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.

Consider the given system

$2x+y+z=-3\n\n 3x-5y+3z=-4\n\n 5x-y+2z=-2$

Write in matrix form as

$\begin{pmatrix}2&1&1\n \:3&-5&3\n \:5&-1&2\end{pmatrix}\begin{pmatrix}x\n \:y\n \:z\end{pmatrix}=\begin{pmatrix}-3\n \:-4\n \:-2\end{pmatrix}$

⇒ AX = b

Writing in Augmented matrix form , [A | b]

$\begin{pmatrix}2&1&1&-3\n 3&-5&3&-4\n 5&-1&2&-2\end{pmatrix}$

Apply row operations to make A an identity matrix.

$R_1\:\leftrightarrow \:R_3$

$=\begin{pmatrix}5&-1&2&-2\n 3&-5&3&-4\n 2&1&1&-3\end{pmatrix}$

$R_2\:\leftarrow \:R_2-(3)/(5)\cdot \:R_1$

$=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 2&1&1&-3\end{pmatrix}$

$R_3\:\leftarrow \:R_3-(2)/(5)\cdot \:R_1$

$=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 0&(7)/(5)&(1)/(5)&-(11)/(5)\end{pmatrix}$

$R_3\:\leftarrow \:R_3+(7)/(22)\cdot \:R_2$

$=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 0&0&(17)/(22)&-(34)/(11)\end{pmatrix}$

$R_3\:\leftarrow (22)/(17)\cdot \:R_3$

$=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 0&0&1&-4\end{pmatrix}$

$R_2\:\leftarrow \:R_2-(9)/(5)\cdot \:R_3$

$=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&0&(22)/(5)\n 0&0&1&-4\end{pmatrix}$

$R_1\:\leftarrow \:R_1-2\cdot \:R_3$

$=\begin{pmatrix}5&-1&0&6\n 0&-(22)/(5)&0&(22)/(5)\n 0&0&1&-4\end{pmatrix}$

$R_2\:\leftarrow \:-(5)/(22)\cdot \:R_2$

$=\begin{pmatrix}5&-1&0&6\n 0&1&0&-1\n 0&0&1&-4\end{pmatrix}$

$R_1\:\leftarrow \:R_1+1\cdot \:R_2$

$=\begin{pmatrix}5&0&0&5\n 0&1&0&-1\n 0&0&1&-4\end{pmatrix}$

$R_1\:\leftarrow (1)/(5)\cdot \:R_1$

$=\begin{pmatrix}1&0&0&1\n 0&1&0&-1\n 0&0&1&-4\end{pmatrix}$

Thus, We obtained an identity matrix

Thus, The solution is (1, -1 , -4)

This involves quite a lot of arithmetic to do manually.

The first thing you do is to make the first number in row 2 = to 0.

This is done by R2 = -3/2 R1 + R2

so the matrix becomes

( 2 1 1) ( -3 )

( 0 -13/2 3/2) (1/2 )

(5 -1 2) (-2)

Next step is to make the 5 in row 5 = 0

then the -1 must become zero

You aim for the form

( 1 0 0) (x)

(0 1 0) (y)

(0 0 1) ( z)

x , y and z will be the required solutions.

2.67 as a simplified fraction someone help pls tysm if u do

Answers

Answer:

2 67/100

Step-by-step explanation:

267/100= 2 67/100 = 2.67

I'll give 100 pts and brainliest if you answer this!!!thank you for the help boo

Perform the operation. Write the answer in standard form.
1. (6 − i) + (9 + 5i)
2. (7 + 3i) + (11 + 2i)
3. (12 + 4i) − (2 − 15i)
4. (3 − 7i) − (3 + 5i)
5. 7 − (2 − 3i) + 6i
6. −16 + (3 + 4i) − 4i
7. 3i(6 − 5i)
8. −2i(8 + 2i)
9. (−5 + i)(8 − 6i)
10. (3 − 6i)(−1 + 7i)
11. (2 + 5i)(2 − 5i)
12. (−3 − i)(−3 + I)
13. (4 + i) 2
14. (5 − 9i) 2
Thank you again <3

Answers

Answer:

1. $4i+15$

2. $5i+18$

3. $-11i+10$

4. $-2i$

5. $9i+5$

6. $-13$

7. $-15i^(2)+18i$

8. $-4i^2-16i$

9. $-6i^2+38i-40$

10. $-42i^2+27i-3$

11. $-25i^2+4$

12. $-i^2+9$

13. $2i+8$

14. $-18i+10$

Step-by-step explanation:

Standard form means to put the terms in order based on their exponent (x³ -> x² -> x -> constant)

1. (6 - i) + (9 + 5i)

$4i+15$

2. (7 + 3i) + (11 + 2i)

$5i+18$

3. (12 + 4i) - (2 - 15i)

$-11i+10$

4. (3 - 7i) - (3 + 5i)

$-2i$

$35i^2+6i-9$

5. 7 - (2 - 3i) + 6i

$7 - 2 + 3i + 6i$

$9i+5$

6. -16 + (3 + 4i) - 4i

$-16 + 3 + 4i - 4i$

$-13$

7. 3i(6-5i)

$18i-15i^2$

$-15i^2+18i$

8. -2i(8+2i)

$-16i+-4i^2$

$-4i^2-16i$

9. (-5 + i)(8 - 6i)

$-40+30i+8i-6i^2$

$-6i^2+38i-40$

10. (3 - 6i)(-1 + 7i)

$-3+21i+6i-42i^2$

$42i^2+27i-3$

11. (2 + 5i)(2 - 5i)

$4-10i+10i-25i^(2)$

$-25i^2+4$

12. (-3 - i)(-3 + i)

$9 -3i + 3i -i^2$

$-i^2+9$

13. (4 + i) * 2

$2i+8$

14. (5 - 9i) * 2

$-18i+10$

:p when I first started answering this I thought the parentheses were being multiplied every time and did 100x more work .-.

Hope it helps <3 :D

What property is illustrated by each statement? 7+(4+4)=(7+4)+4A. Inverse property of addition B. Associative property of addition C. Commutative property of addition

Answers

B
This property dictates that you can add regardless of how the numbers are grouped.

Divide. Will mark brainliest.

Answers

Answer:

7t^5 - t^3

6x -3 +2x/y

Step-by-step explanation:

A. (7t^8 - t^6)/t^3

Separate into 2 fractions

(7t^8/t^3) - (t^6)/t^3

Remember a^b / a^c = a^ (b-c)

7 t^(8-3) - t^(6-3)

7t^5 - t^3

B (12x^2y - 6xy +4x^2)/2xy

Separate into 3 fractions

12x^2y/2xy - 6xy/2xy +4x^2/2xy

Remember a^b / a^c = a^ (b-c)

12/2 x^(2-1) y^(1-1) - 6/2 x/x * y/y +4/2 x^(2-1) /y

6 x y^0 -3*1*1 +2 x/y

Remember that x^0 = 1

6x -3 +2x/y

Tristan records the number of customers who visit the store each hour on a Saturday. His data representing the first seven hours are 15, 23, 12, 28, 20, 18, and 23. How many customers visited the store during the eighth hour if the median number of customers per hour did not change?16
19
20
23

Answers

The number of Customers that visited the store during the eight hour if the median number of customers didn't change is; C: 20

What is the Median?

We are given the data representing the first seven hours as; 12, 15, 18, 20, 23, 23, 28. Here; n=7

Thus;

Median = (n + 1)/2 = (7 + 1)/2

Median = 4th term

Thus, the median is 20.

When one data is added, n = 8. Thus;

Median will be the average of the 4th and 5th term. Since the median does not change, it means that the median number of customers per hour is still 20.

Read more baout Median at; brainly.com/question/1552529

Answer:

Step-by-step explanation:

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