Groups of students are measuring the masses of several rocks. They have a scale that can show readings in pounds or kilograms. The teacher requires that they all make their measurements in kilograms.Why would the teacher make a decision like this?

Choose 1 answer:

(Choice A) A kilogram is larger than a pound, so the scale could measure more massive rocks.

(Choice B) Accurate measurements cannot be made in pounds.

(Choice C) Pounds cannot be converted to kilograms.

(Choice D) It is easier to compare measurements when using the same unit system.

Answers

Answer 1

Answer:

Answer:

(D). It is easier to compare measurements when using the same unit system.

Explanation:

Kilograms are the standard unit of mass in the metric system, while pounds are the standard unit of mass in the imperial system.

The two systems are not directly convertible, so it would be difficult to compare measurements made in different units.

Therefore, the teacher requires that the students make their measurements in kilograms to simplify the comparison of their results.

So, answer (D). It is easier to compare measurements when using the same unit system.

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Let's see the other option:

Choice (A) is incorrect because a kilogram is not larger than a pound. A kilogram is equal to about 2.2 pounds.
Choice (B) is incorrect because accurate measurements can be made in pounds.
Choice (C) is incorrect because pounds can be converted to kilograms. The conversion factor is 1 kilogram = 2.2 pounds.

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Answer 2

Answer:

Answer:

Choice D

Explanation:

The correct answer is (Choice D) It is easier to compare measurements when using the same unit system.

When conducting scientific experiments or measurements, it is crucial to maintain uniformity in the units of measurement to facilitate accurate comparisons and analysis. By requiring all students to measure the masses of rocks in kilograms, the teacher ensures consistency and eliminates any potential confusion that may arise from using different unit systems.

Using the same unit system allows for straightforward comparisons and calculations without the need for converting between units. It simplifies data analysis and interpretation, which is crucial for scientific accuracy and understanding. By standardizing the unit of measurement to kilograms, the students can directly compare the masses of rocks and draw meaningful conclusions from their data.

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A juggler throws a bowling pin straight up with an initial speed of 9.20m/s. How much time elapses before the pin reaches the juggler's hands?

Answers

Answer:

1.87 s

Explanation:

Initial speed of throw = 9.20 m/s

Net vertical displacement = 0

The bowling pin would be in free fall i.e. a = 9.8 m/s²

Use the second equation of motion:

s = ut + 0.5at²

0 = (9.20)t-0.5(9.8)(t²)

9.20 = 4.9 t

⇒t = 1.87 s

Thus, the total time of flight, the time elapses before the bowling pin falls in juggler's hand is 1.87 s.

A juggler throws a bowling pin straight up with an initial speed, the time that elapses before the pin reaches the juggler's hands is 1.88 s.

Given:
Initial speed, u = 9.2 m/s

The time can be calculated from the second equation of motion. The second equation of motion provides a relation between height, initial speed, acceleration, and time respectively.

From the second equation of motion:

h = ut + at²

When the ball reaches the hands, the distance becomes zero. Therefore, the time is:

0 = 9.2t -0.5 × 9.8t²

9.8t = 18.4

t = 18.4÷ 9.8

t = 1.88 s

Hence, the time that elapses before the pin reaches the juggler's hands is 1.88 s.

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