PHYSICS HIGH SCHOOL

You're in an airplane that flies horizontally with speed 1100 km/h (300 m/s ) when an engine falls off. Neglecting air resistance, assume it takes 26 s for the engine to hit the ground.Find the height of airplane.

Answers

Answer 1

Answer:

Answer:

The height of the airplane is 3312.4 meters.

Explanation:

Given that,

Speed of the airplane, v = 1100 km/h = 300 m/s

It takes 26 s for the engine to hit the ground. We need to find the height of the airplane. Using second equation of motion to find it as :

$h=ut+(1)/(2)at^2$

Here, u = 0 and a = g

$h=(1)/(2)gt^2\n\nh=(1)/(2)* 9.8* (26)^2\n\nh=3312.4\ m$

The height of the airplane is 3312.4 meters.

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Why can't alpha particles penetrate deeply into solids? Alpha particles have low mass. Alpha particles have high mass. Alpha particles have low velocity. Alpha particles have high velocity.

Answers

Alpha particles have both high mass and low velocity, but it would be the former that determines why they can't penetrate. An alpha particle is made of two protons and two neutrons, which is quite a large mass for a particle. This large mass keeps it from penetrating too deeply into anything, since it will essentially "get stuck" when it comes too near to another atom.
So the answer, I believe, is B. Alpha particles have high mass.

The answer is the Alpha Particles have low velocity

A force of 5 N gives to mass my and an acceleration of 8m/s2 and a mass m2an acceleration of 24m/s2. What acceleration would it give if both masses are
tied together

Answers

Answer:

a=6m/sec²

Explanation:

f=5 N

a1=8m/sec²

a2=24m/sec

m1=f/a1=5/8kg

m2=f/a2=5/24kg

New, f=(m1+m2)a

a=5/5/8+5/24=5/15+5/24=24*5/20

a=6m/sec²

As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.05 m 1.05 m long rod as you jog at 3.27 m/s 3.27 m/s , holding the rod perpendicular to your direction of motion. What is the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.275 mV 0.275 mV across the rod? Express the answer in milliteslas.

Answers

Answer:

The strength of the magnetic field is 0.08 mT

Explanation:

Given:

Length of rod $l = 1.05$ m

Velocity of rod $v = 3.27$ $(m)/(s)$

Induced emf $\epsilon = 0.275 * 10^(-3)$ V

According to the faraday's law

We know that the induced emf of rod is given by,

$\epsilon = Blv$

Where $B =$ magnetic field

For finding the magnetic field,

$B = (\epsilon )/(lv)$

$B = (0.275 * 10^(-3) )/(1.05 * 3.27)$

$B = 0.08 * 10^(-3)$

$B = 0.08$ mT

Therefore, the strength of the magnetic field is 0.08 mT

A mountain climber ascends a mountain to its peak. The peak is 12,470 ft above sea level. The climber then descends 80 ft to meet a fellow climber. Find the climber's elevation above sea level after meeting the other climber. A. -12,390 ft. B. 12,550 ft. C. 11,670 ft. D. 12,930 ft

Answers

The answer is 12,390 ft.

At first, a climber is at 12,470 ft above sea level. But then, he goes down 80 ft to meet a fellow climber. So, this simply needs to be distracted:
12,470 ft - 80 ft = 12,390 ft
This is the elevation above sea level at which he meet the other climber.

Ball A has mass 5.0 kg and is moving at -3.2 m/s when it strikes stationary ball B, which has mass 3.9 kg, in a head-on collision. If the collision is completely inelastic, what is the common velocity of balls A and B?

Answers

Momentum conservation in a completely inelastic collision works like this:
mA*vA+mB*vB=v(mA+mB)

Since B was initially stationary pB=0.
Plugging in numbers gives:
5*(-3.2)=v(5+3.9)
v= -1.79 m/s to the left.

Answer:

A.) -0.40 m/s

B.) -3.60 m/s

C.) -1.80 m/s

Explanation:

By the law of momentum conservation:-

=>m1u1 + m2u2 = m1v1 + m2v2

=>5 x (-3.2) + 0 = 5v1 + 3.9v2

=>1.28v1 + v2 = -4.10 ---------------(i)

for elastic collision:-

=>v1 - v2 = u2 - u1

=>v1 - v2 = 0 - (-3.2)

=>v1 - v2 = 3.2 ------------------(ii)

by (i) + (ii) :-

=>2.28v1 = -0.90

=>v1 = -0.40 m/s

=>v2 = -3.60 m/s

=>m1u1+m2u2 = (m1+m2)v

=>5 x (-3.2) + 0 = (5 + 3.9) x v

=>v = -1.80 m/s

How will you join three resistances, each of 2 ohm so that the effective resistance is 3 ohm?

Answers

First I will parallel two of the resistors, creating a net 1 ohm. Then I will series that with the remaining 2-ohm resistor, resulting in 3 ohms.

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