in a cylinder cup, AB=5cm, BC= 12cm. AD is a straw that passes point A and C and CD= 2cm. the length of the straw is:

Answers

Answer 1

Answer:

Answer:

17.13 cm.

Step-by-step explanation:

In the given scenario, we have a cylinder cup with points A, B, and C, and a straw AD that passes through points A and C. The measurements are as follows:

AB = 5 cm

BC = 12 cm

CD = 2 cm

We can use the Pythagorean theorem to find the length of the straw AD. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, AD is the hypotenuse, and AC and CD are the other two sides. We can write the Pythagorean theorem equation as:

AD^2 = AC^2 + CD^2

Given that AC is the sum of AB and BC:

AC = AB + BC

AC = 5 cm + 12 cm

AC = 17 cm

Now we can substitute the values into the Pythagorean theorem equation:

AD^2 = 17^2 + 2^2

AD^2 = 289 + 4

AD^2 = 293

Taking the square root of both sides to solve for AD:

AD = √293

AD ≈ 17.13 cm

So, the length of the straw AD is approximately 17.13 cm.

Answer 2

Answer:

Answer:

17.13 cm.

Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Answers

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Answers

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Answers

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Answers

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Answers

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