Which digit is in the tenths place of 1,860.5

Answers

Answer 1
Answer:

5

In the number 1,860.5, the digit in the tenths place is "5." The tenths place is the first digit to the right of the decimal point, and in this case, it holds the value of 5 tenths or 0.5.

Answer 2
Answer:

Answer:its the 6

Step-by-step explanation:trust


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Please help math 25 points

Answers

The answer is c folk

The answer is C my mans

The graph shows the ages of different concertgoers who have backstage passes.Which statement is true about the graph?

Answers

In the graph you can see that there are a couple of concertgoers that are way older than the rest.
the statement that is true about the graph would be : the two holders of the passes whose ages are above 40 make the means age higher than the median age

hope this helps

Hal is asked to write an exponential function to represent the value of a $10,000 investment decreasing at 2% annually. What multiplicative rate of change should Hal use in his function?

Answers

For exponential growth or decrease there is a general formula given:

P(t) = P(0) [exp(rt)]where,P(t) is the investment remaining at time t,P(0) is the investment at time 0, initial investment andr is the exponential rate of decrease.

10,000 * 0.02 = 200
10,000 - 200 = 9,800 value after year 1

P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1

r = loge (0.98)  = ln (0.98) = -0.0202

P(t) = P(0)[exp(-0.0202t)]

Answer: 0.98

Step-by-step explanation:

The person above me is wrong, the correct answer on ED. is 0.98

If 20 coins are tossed, find the probability that they'll all land on tails.

Answers

The probability would be split for this problem cause knowing with 20 coins , you can split that even amount ... here's what I would do..


Michelle has 20 coins , but only half of them land on heads and others on tails


As for a half , halves are always equaling to 1/2 or 50 (%)  knowing we have 20 , you can evenly split that number of coins in a equal position

So ask your self .. what is half of 20? hmmm .. oh I got it , its 10! so knowing you have 20 but then later you split into half which is 10 ... meaning and knowing you have a 50% probability of getting the 20 coins hitting onto tails

hope this helps!

Katie ran 200 meters in 32 seconds. What was Katie's speed?

Answers

Answer:

Step-by-step explanation:

200 divided by 32 =6.25 or 6

Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.

Answers

Answer:

Option (a) is correct.

The solution is (1, -1 , -4)

Step-by-step explanation:

Given:

A system of equation having 3 equations,

2x+y+z=-3\n\n 3x-5y+3z=-4\n\n 5x-y+2z=-2

We have to solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.  

 Consider  the given system

2x+y+z=-3\n\n 3x-5y+3z=-4\n\n 5x-y+2z=-2

Write in matrix form as

\begin{pmatrix}2&1&1\n \:3&-5&3\n \:5&-1&2\end{pmatrix}\begin{pmatrix}x\n \:y\n \:z\end{pmatrix}=\begin{pmatrix}-3\n \:-4\n \:-2\end{pmatrix}

⇒  AX = b

Writing in Augmented matrix form , [A | b]

\begin{pmatrix}2&1&1&-3\n 3&-5&3&-4\n 5&-1&2&-2\end{pmatrix}

Apply row operations to make A an identity  matrix.

R_1\:\leftrightarrow \:R_3

=\begin{pmatrix}5&-1&2&-2\n 3&-5&3&-4\n 2&1&1&-3\end{pmatrix}

R_2\:\leftarrow \:R_2-(3)/(5)\cdot \:R_1

=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 2&1&1&-3\end{pmatrix}

R_3\:\leftarrow \:R_3-(2)/(5)\cdot \:R_1

=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 0&(7)/(5)&(1)/(5)&-(11)/(5)\end{pmatrix}

R_3\:\leftarrow \:R_3+(7)/(22)\cdot \:R_2

=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 0&0&(17)/(22)&-(34)/(11)\end{pmatrix}

R_3\:\leftarrow (22)/(17)\cdot \:R_3

=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&(9)/(5)&-(14)/(5)\n 0&0&1&-4\end{pmatrix}

R_2\:\leftarrow \:R_2-(9)/(5)\cdot \:R_3

=\begin{pmatrix}5&-1&2&-2\n 0&-(22)/(5)&0&(22)/(5)\n 0&0&1&-4\end{pmatrix}

R_1\:\leftarrow \:R_1-2\cdot \:R_3

=\begin{pmatrix}5&-1&0&6\n 0&-(22)/(5)&0&(22)/(5)\n 0&0&1&-4\end{pmatrix}

R_2\:\leftarrow \:-(5)/(22)\cdot \:R_2

=\begin{pmatrix}5&-1&0&6\n 0&1&0&-1\n 0&0&1&-4\end{pmatrix}

R_1\:\leftarrow \:R_1+1\cdot \:R_2

=\begin{pmatrix}5&0&0&5\n 0&1&0&-1\n 0&0&1&-4\end{pmatrix}

R_1\:\leftarrow (1)/(5)\cdot \:R_1

=\begin{pmatrix}1&0&0&1\n 0&1&0&-1\n 0&0&1&-4\end{pmatrix}

Thus, We obtained an identity matrix

Thus, The solution is (1, -1 , -4)

This  involves quite a lot of arithmetic to do manually.

The first thing you do is to make the first number in  row 2  = to 0.

This is done by R2 = -3/2 R1 + R2

so the matrix becomes

( 2        1          1)    ( -3 )

( 0    -13/2   3/2)   (1/2 )

(5       -1           2)  (-2)

Next step is to make  the 5 in row 5  = 0  

then  the -1  must become zero

You aim  for the form

( 1 0 0) (x)

(0 1 0) (y)

(0 0 1) ( z)

x , y and z will be the required solutions.