MATHEMATICS HIGH SCHOOL

How to distribute this problem:
(x-8)^2 + 16

Answers

Answer 1

Answer:

Answer:

We conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

Step-by-step explanation:

Given the equation

$\left(x-8\right)^2\:+\:16$

First, solve (x - 8)²

Apply Perfect Square formula: (a - b)² = a² - 2ab + b²

$a=x,\:\:b=8$

$\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2$

$=x^2-16x+64$

so the expression becomes

$\left(x-8\right)^2+16=x^2-16x+64+16$

$=x^2-16x+80$ Add the numbers: 64+16=80

Therefore, we conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

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Simplify
8v+w+7-8v+2w
4c^2 +6c-3c^2-2c-3
Z^3+5z+3z^2+1-4-2z^2

Answers

1) 8v+w+7-8v+2w

=w+7+2w

=3w+7

-----------------------------

2) 4c^2+6c-3c^2-2c-3

=c^2+6c-2c-3

=c^2+4c-3

-------------------------------

3) z^3+5z+3z^2+1-4-2z^2

=z^3+z^2+5z+1-4

=z^3+z^2+5z-3

Solve two step equation 3=9+n/2

Answers

Answer:

n = -12

Step-by-step explanation:

hope it helped , darling .

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Find the perimeter of the figure. Round to the nearest tenth if
necessary.

Answers

Answer:

Step-by-step explanation:

15+ $\sqrt[18]$ $\sqrt[2]{18}$ + 1.5pi

19.7+ $\sqrt[2]{18}$

23.95

From 12 prepared songs, a bandchooses 3 to perform on a TV show. One
song will be played at the beginning of
the show, one in the middle, and one at
the end. Tell how many different set lists
are possible. Then tell if the situation
involves permutations or combinations.

Answers

Answer:

1320 different set lists are possible

Step-by-step explanation:

We have a set of 12 elements (12 songs)

There can be NO songs repeatedly

The order of the songs is important because One song will be played at the beginning of the show, one in the middle, and one at the end.

So as the order of selection is important we must use permutations.

The formula for permutations is:

$nPr=(n!)/((n-r)!)$

where n is the number of items you can choose and choose r from them

In this case we know that:

$n=12$ , $r=3$

Then:

$12P3=(12!)/((12-3)!)$

$12P3=(12!)/(9!)$

$12P3=1320$

(please help me. ) (I screenshot the question and choices )

Answers

its A
because sin A is CB/AB
and cos A is AC/AB

It is the first one
We know that Sin Ф= $(opposite)/(hypotenuse)$
And Cos Ф= $(adjacent)/(hypotenuse)$
So the sides go accordingly
The picture i have attached will be helpful

Express 0.59 as a fraction....