Answer:
Figure 1's surface area: 550
Figure 2's surface area: 530
Figure 3's surface area: 790
So, the order of the figures' surface areas is: Figure 2 < Figure 1 < Figure 3.
Step-by-step explanation:
Bearing in mind that the surface area of a 3D object is the total area of its surface (that is the sum of the areas of its faces), we can count the number of distinct shapes in each figure, calculate their areas and add them up. Be careful not to add the faces that are "inside".
Figure 1
Its surface area consists of 13 squares of 5x5and 3 rectangles of 15x5. So, its surface area is (13x25 + 3x75)
Figure 2
Its surface area consists of 6 squares of 5x5, 3 rectangles of 17x5, 1 rectangle of 13x5 and 2 triangles of base 12 feet and height 5 feet. So, its surface area is (17x5x3+6x5x5+13x5+12x5x2:2)
Figure 3
Its surface area consists of 2 rectangles of 12.5x5, 1 rectangle of 11x5, 2 triangles of base 12 feet and height 5 feet, 1 rectangle of 11x13, 2 rectangles of 12.5x11 and 1 rectangle of 12x11.
So, its surface area is (2x12.5x5+11x5+2x12x5:2+11x13+2x12.5x11+12x11)
Answer:
Least surface area to greatest surface area:
Blue - Red - Green
Step-by-step explanation:
All the surfaces of the shapes are rectangles, then their surface is computed as:
Surface = Length*Width
Blue figure
Area of the top:
5*5 + 5*5 + 5*5 + 5*5 + 5*5 = 125 ft^2
Area of the sides:
2*(5*10) = 100 ft^2
Area of the bottom:
10*5 = 50 ft^2
Area of the front and the back
2*(5*5 + 15*5) = 200 ft^2
Total: 125 + 100 + 50 + 200 = 475 ft^2
Red figure
Area of the top:
5*5 + 13*5 = 90 ft^2
Area of the left side:
5*10 = 50 ft^2
Area of the right side:
5*5 = 25 ft^2
Area of the bottom:
17*5 = 85 ft^2
Area of the front and the back:
2*(17*5 + 12*5/2 + 5*5) = 280 ft^2
Total: 90 + 50 + 25 + 85 + 280 = 530 ft^2
Green figure
Area of the top:
12.5*11 + 13*11 = 280.5 ft^2
Area of the left side:
11*5 = 55 ft^2
Area of the bottom:
(12.5+12)*11 = 269.5 ft^2
Area of the front and the back:
2*(12.5*5 + 12*5/2) = 185 ft^2
Total: 280.5 + 55 + 269.5 + 185 = 790 ft^2
Answer:
B. 2x + 3 ≥ 11 or 4x - 7 ≤ 1
Step-by-step explanation:
Given compound inequality,
In option A,
2x + 3 ≥ 11 and 4x - 7 ≤ 1
⇒ 2x ≥ 8 and 4x ≤ 8
⇒ x ≥ 4 and x ≤ 2
2x + 3 ≥ 11 and 4x - 7 ≤ 1 can not be the correct inequality,
In option B,
2x + 3 ≥ 11 or 4x - 7 ≤ 1
⇒ 2x ≥ 8 or 4x ≤ 8
⇒ x ≥ 4 or x ≤ 2
Which is shown in the given graph,
Thus, 2x + 3 ≥ 11 or 4x - 7 ≤ 1 is the correct compound inequality,
In option C,
2x + 3 > 11 or 4x - 7 < 1
⇒ 2x > 8 or 4x < 8
⇒ x > 4 or x < 2
So, which is not shown in the graph,
2x + 3 > 11 or 4x - 7 < 1 can not be the correct compound inequality,
In option D,
2x + 3 ≥ 11 or 4x - 7 ≥ 1
⇒ 2x ≥ 8 or 4x ≥ 8
⇒ x ≥ 4 or x ≥ 2
Which is not shown in the graph,
2x + 3 ≥ 11 or 4x - 7 ≥ 1 is not the correct compound inequality.
B.. 4 is less than or equal to x, 2 is greater or equal to x
Answer:
32c +16
Step-by-step explanation:
4(8c+4)
Multiply 4 to the terms inside the parentheses
4*8c +4*4
32c +16
The factorization of 60 is
2 times of 30 is 60.
3 times of 20 is 60.
4 times of 15 is 60.
5 times of 12 is 60.
6 times of 10 is 60.
We have to factories the number 60.
So, the factors of 60 as
60 = 2 x 30
60 = 3 x 20
60 = 4 x 15
60 = 5 x 12
60 = 6 x 10
Then, 60 can be
2 times of 30 is 60.
3 times of 20 is 60.
4 times of 15 is 60.
5 times of 12 is 60.
6 times of 10 is 60.
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