A geostationary orbit, also known as a geosynchronous equatorial orbit, is a specific type of circular orbit around the Earth. In this orbit, a satellite's orbital period matches the Earth's rotation period, which is approximately 24 hours. This causes the satellite to appear stationary relative to a fixed point on the Earth's surface, which is why it's commonly used for communication, weather, and broadcasting satellites.
To achieve this, the satellite needs to be at a specific height above the Earth's surface. The altitude at which a satellite will have a period of one day (24 hours) is called the geostationary altitude or the geostationary orbit height.
The calculation to determine this altitude involves using the formula for the orbital period of a satellite:
Where:
- \( T \) is the orbital period (24 hours in this case)
- \( G \) is the gravitational constant
- \( M \) is the mass of the Earth
- \( r \) is the radius of the satellite's orbit (distance from the center of the Earth to the satellite)
Solving for \( r \) with the known values of \( T \), \( G \), and \( M \), you'll find that the satellite needs to be approximately 35,786 kilometers (22,236 miles) above the Earth's surface to have an orbital period of one day.
This altitude allows the satellite to complete one orbit around the Earth in the same amount of time it takes for the Earth to complete one rotation on its axis, effectively staying in the same position relative to a specific point on the Earth's equator.
B. Raise the object farther off the ground
C. Lower the object towards the ground
D. Allow the object to roll on the ground
Answer:
B Raise the object farther off the ground
To increase the gravitational potential energy of an object without altering its mass or gravity, you would need to raise the object to a greater height. The potential energy is determined by the object's mass, its height, and the gravitational force, as shown by the formula potential energy=mgh.
To increase the gravitational potential energy of an object without changing its mass and gravity, you could raise the object farther off the ground. This is because gravitational potential energy is a function of an object's mass, height, and acceleration due to gravity, as represented by the formula potential energy = mgh, m being mass, g being gravity, and h being height.
Moving the object to a greater height without acceleration or carrying the object with or without acceleration at the same height will not result in an increased potential energy. Only by raising the object to a higher position or altitude, you increase its potential energy.
In essence, the principle involves work done against the gravity. When an object is raised to a higher elevation, work is done against gravity. This work gets stored as potential energy in the object-Earth system. Thus, the higher the position of the object, the higher would be its gravitational potential energy.
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Answer:
5×10^4 kg
Explanation:
pressure= force/Area
area= 5m^2
pressure = 1×10^5 Pa
1×10^5=mg/5 (weight will be the force)
5×10^5=m×10 (gravitational field strength of the earth)
5×10^5×10^-1 =m
mass=5×10^4 kg!
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Answer:
In cold air, the molecules mover slower because of the colder tempature, however, in hot air they move faster this is because the molecules are being heated up. Hot = faster, cold = slower
Explanation:
Answer:
Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.
Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.
So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:
At,
t=0, v=0 m/s
t=1, v=0+10 m/s;
t=2, v=0+10+10 m/s;
t=3, v=0+10+10+10 m/s;
This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:
v = u + at
Hope this Answer Helps!!
Explanation:
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It means that the vehicle's speed increases at the rate of 10m/s every second.
At any time, it's speed is 10 m/s faster than it was 1 second earlier.