Can the normal force on an object be directed horizontally?

Answers

Answer 1
Answer:

For this case, the first thing you should do is take into account the definition of normal force.

By definition, we have:

  • The normal force is that which is exerted on an object that is perpendicular to the surface.

If we define the coordinate system as:

  1. Horizontal axis points to the right
  2. Vertical axis points up

Then An object resting on a wall can have normal force in a horizontal direction.

Answer:

The normal force is perpendicular to the surface. The direction can be horizontal. Example: an object on a wall.


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A water wave travels across a 42-meter wide pond in 7.0 seconds. The speed of the wave is _____. 292 m/s 49 m/s 6.0 m/s 0.17 m/s

Answers

           Speed  =  (distance covered) / (time to cover the distance).

The speed of anything that covers 42 meters in 7 seconds is

               (42 meters)  /  (7.0 seconds)

           =    (42 / 7.0)      (meters/second)

           =             6.0 m/s . 

Answer:

6.0 m/s

Explanation:

A water wave travels across a 42-meter wide pond in 7.0 seconds. The speed of the wave is _____.

292 m/s

49 m/s

6.0 m/s

0.17 m/s

A car moving with a velocity of 20 meters/second has1.8 * 105 joules of kinetic energy. What is the mass of the car?

Answers

Kinetic energy is the product of mass and the square of the velocity of the moving object. In this case, we substitute the given data, that is 1.8 x10^5 joules = m * (20 m/s2)^2. Extracting the mass, the mass of the car therefore is equal to 450 kg

Explanation :

Given that,

Velocity of the car, v = 20 m/s

Kinetic energy of the car, E_k=1.8* 10^5\ J

Kinetic energy is given by :

E_k=(1)/(2)mv^2

m=(2E_k)/(v^2)

So, m=(2* 1.8* 10^5\ J )/((20\ m/s)^2)

m = 900 kg

Hence, the mass of the car is 900 kg

A long solenoid has 1400 turns per meter of length, and it carries a current of 4.9 A. A small circular coil of wire is placed inside the solenoid with the normal to the coil oriented at an angle of 90.0˚ with respect to the axis of the solenoid. The coil consists of 42 turns, has an area of 1.2 × 10-3 m2, and carries a current of 0.45 A. Find the torque exerted on the coil.

Answers

Answer:

The torque on the coil is 1.955* 10^(- 4)\ N-m

Solution:

No. of turns per meter length, n = 1400 turns\m

Current, I = 4.9 A

Angle, \theta = 90.0^(\circ)

No. of turns of coil, N = 42 turns

Area, A = 1.2* 10^(- 3)m^(2)

Current in the coil, I' = 0.45 A

Now,

To calculate the exerted torque on the coil:

The magnetic field, B produced inside the coil is given by:

B = n\mu_(o)I

B = 1400* 4\pi times 10^(- 7)* 4.9 = 8.62* 10^(- 3)\ T

Now, the torque exerted is given by:

\tau = I'NAB

\tau = 0.45* 42* 1.2* 10^(- 3)* 8.62* 10^(- 3) = 1.955* 10^(- 4)\ N-m

Answer:

T\approx 1.95* 10^(-4) N.m

Explanation:

Given:

A long solenoid having

no. of turns per meter, n =1400

current, I = 4.9 A

A small coil of wire placed inside the solenoid

angle of orientation with respect to the axis of the solenoid, \theta=90\degree°

no. of turns in the coil, N = 42

area of the coil, a= 1.2* 10^(-3) m^2

current in the coil, i =0.45 A

We have for torque:

T=n.i.a.B. sin\theta.......................(1)

B=\mu_(0) .n.I................................(2)

where:

B= magnetic field

\mu_0=The permeability of free space =4\pi*10^(-7) T.m.A^(-1)

Substitute B from eq. (2) into eq. (1) we have:

T=n.i.a.(\mu_0.N.I ).sin\theta

putting the respective values in above eq.

T=42* 0.45* 1.2* 10^(-3)* 4\pi*10^(-7) * 1400* 4.9* sin 90^(\circ)

T\approx 1.95* 10^(-4) N.m

PLEASE help me with these questions as soon as possible i need to turn it in!!!!A 60 watt light bulb uses 60 joules of electrical energy every second. However, only 6 joules of electrical energy is converted into light energy each second.
a. What is the efficiency of the light bulb? Give your answer as a percentage.

b. What do you think happens to the “lost” energy?

19. The work output is 300 joules for a machine that is 50% efficient. What is the work input?

20. A machine is 75% efficient. If 200 joules of work are put into the machine, how much work output does it produce?

Answers

a. I believe this might be the answer but
6 J/60 J= .1
.1 x 100= 10%

b. I'm not sure of this question


19. I'm not sure if I did this correct way or if there is a better way (I'm rusty) 
300 J/.50 %= 600
600/100= 6 (answer)


20. (200 J)(.75%) = 150 (answer)
Check:
Efficiency: output/input x 100
150 J/200 J= .75
.75 x 100= 75%

. A ray of monochromatic light (f = 5.09 × 1014hertz) in air is incident at an angle of 30.°
on a boundary with corn oil. What is the angle of refraction, to the nearest degree, for this
light ray in the corn oil?

Answers

The angle of refraction of light ray in the corn oil is 20°.

What is angle of Refraction?

Angle of refraction is the angle the refracted light ray makes with the normal to the oil-air interface.

Given data:

Angle of incidence = 30°

Analysis:

The refractive index of oil is 1.47.

Using the formula for refractive index(n) = (sini)/(sinr)

1.47 = (sin 30)/(sin r)

1.47(sin r) = sin 30

sin r = (sin 30)/(1.47)

sin r = 0.3401

r = arc sin(0.3401)

r = 19.88° which is approximately 20°

Learn more about Refraction : brainly.com/question/10729741

#SPJ2

Answer:

its 20 degrese

Explanation:

What makes an inductor/capacitor different from other passive circuit elements? a) Inductors store energy in a magnetic field, while capacitors store energy in an electric field. b) Inductors resist changes in current, while capacitors resist changes in voltage. c) Inductors are used in AC circuits, while capacitors are used in DC circuits. d) Inductors are always connected in series, while capacitors are always connected in parallel.

Answers

Answer:

Give any one cultural practice