Result:
5/5 : 1/2 = 5/5 · 2/1 = 5 · 2/5 · 1 = 10/5 = 2
To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.
Hi There!
Find Common Denominators:
2 5/8 = 2 15/24
5/6 = 20/24
1 1/8 = 1 3/24
Turn Into Improper Fractions:
2 15/24 = 63/24
20/24 = 20/24
1 3/24 = 27/24
Add:
= (63/24 + 20/24) + 27/24
= (83/24) + 27/24
= 110/24
Simplify:
110/24 = 4 14/24 = 4 7/12
Answer:
4 7/12
Hope This Helps :)
4/18/18
II
III
IV
The number 6 - 8i is located in the thirdquadrant of the complex plane.
Option C is the correct answer.
The term "quadrants" usually refers to the four regions of the Cartesian plane, which is a two-dimensional coordinate system.
The plane is divided into four regions called quadrants, labeled I, II, III, and IV, which are numbered counterclockwise starting from the upper right quadrant (I).
Quadrant I: The point has positive x and positive y coordinates.
Quadrant II: The point has negative x and positive y coordinates.
Quadrant III: The point has negative x and negative y coordinates.
Quadrant IV: The point has positive x and negative y coordinates.
We have,
To determine the quadrant where the complexnumber 6 - 8i is located, we need to consider the signs of the real and imaginary parts of the number.
The realpart of the number is 6, which is positive, indicating that the number lies to the right of the origin.
The imaginarypart of the number is -8i, which is negative, indicating that the number lies below the origin.
Therefore,
The number 6 - 8i is located in the thirdquadrant of the complex plane.
Learn more about quadrants here:
#SPJ7
Answer:
IV
Step-by-step explanation:
The 6 is to the right of the x axis ( positive x) and the -8i is below the x axis to the right.
Please help i will give metal. can you guys help me i will apreciate it.
A) John
B) Raj
C) Tajika
D) Sue Lee
Choose 1 answer:
(Choice A)
1≤t≤4
(Choice B)
−4≤t≤−3
(Choice C)
−2≤t≤0
(Choice D)
−2≤t≤4
Answer:
In the interval of - 2 ≤ t ≤ 4, the average rate of change is zero.
Step-by-step explanation:
The function is given to be ............ (1)
(i) Now, for 1 ≤ t ≤ 4, we will put t = 1 and t = 4.
So, g(1) = 5, g(4) = - 4. {From equation (1)}
Hence, g(1) ≠ g(4)
(ii) Now, for - 4 ≤ t ≤ - 3, we will put t = - 4 and t = - 3.
So, g(- 4) = - 20, g(- 3) = - 11. {From equation (1)}
Hence, g(- 4) ≠ g(- 3)
(iii) Now, for -2 ≤ t ≤ 0, we will put t = - 2 and t = 0.
So, g(- 2) = - 4, g(0) = 4. {From equation (1)}
Hence, g(- 2) ≠ g(0)
(iv) Now, for - 2 ≤ t ≤ 4, we will put t = - 2 and t = 4.
So, g(- 2) = - 4, g(4) = - 4. {From equation (1)}
Hence, g(- 2) = g(4)
Therefore, in the interval of - 2 ≤ t ≤ 4, the average rate of change is zero. (Answer)