Evaluate, 2 x (390 - [5 x (10 - 4 divided by 2)] + 15) x 2= ?

Answers

Answer 1
Answer: the answer is 1460 because use math equations to break it down
Answer 2
Answer: 2 * (390 - [5 * (10 - (4)/(2))] + 15) * 2= x \n 2 * (390 - [5 * (10 - 2)] + 15] * 2 = x \n 2 * (390 - [5 * 8] + 15) * 2 = x \n 2 * (390 - 40 + 15) * 2 = 2 * (365) * 2 = x \n 730 * 2 = x \n 1460 = x

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Greg ran 3 times as far as jed.rj ran 0.1times as far as Greg. If jed ran25 yards, how far did Greg and rj run

Answers

Greg's distance is 3 times than Jed. so, 25 yards * 3 = 75 yards. And RJ ran only 0.1 times than Greg (75 yards). So, it should be 7.5 yards

CLAIRES BACKYARD IS IN THE SHAPE OF A RECTANGLE AND HAS A LENGTH OF 19.5 feet . It cost her $945.00 to fence in the yard. If fencing cost $15.00 per foot, what is the width of Claires backyard? Please explain how to solve it

Answers

You need to know the formula for the perimeter of a rectangle. We won't use it right away, but it is pertinent information.
P = 2 ( l + w )
Now, we know that the fencing costs $15.00 per foot, and that the length is 19.50 feet.
We first need to find the price of one "length" side of the fence.
To do this, multiply 19.50 by 15.00
19.50 x 15.00 = 292.5
Next, we look at the perimeter equation to see what we can plug in where.
P = 2 ( l + w )
We can put in the total price of the fencing for the yard as P, and the amount of one length side of the fence as l.
945.00 = 2 ( 292.5 + w )
And now, we simply solve for w.
945.00 ÷ 2 = ( 2 ( 292.5 + w ) ) ÷ 2
472.5 = 292.5 + w
472.5 - 292.5 = 292.5 + w - 292.5
w = 180
It costs $180 for one "width" side of the fence.
To find out how many feet that is, we do the opposite of what we did with the length. Instead of multiplying by $15.00, we divide by $15.00
$180.00 ÷ $15.00 = 12
The width of Claire's backyard is 12 feet.

the sum of Marys age and her moms age is 67.  Three times Marys age increased by 7 is her moms age.  How old is Mary and her mother

Answers

Sove the system:

x: Mary´s age
y: Mom´s age:

x + y = 67
3x + 7 = y

Replace y in the first equation:

x + 3x + 7 = 67
4x = 67 - 7
4x = 60
x = 15 yrs.

y = 67  - 15 = 52 yrs
Labels:
-- Mary's age = D (for 'daughter')
-- Mom's age = M (for 'mom')

The problem says 2 things:

         D + M = 67
and
       3D + 7 = M .

Let's subtract 'M' from each side of the first one:  D = 67 - M

Now we can plug that into the second one, in place of 'D'.
 
       3D          + 7 = M

       3(67 - M) + 7 = M .

Clear the parentheses on the left side.  I assume you know how to do that.

       201 - 3M + 7 = M

Add 3m to each side:

       201        + 7 = 4M

       208              = 4M

Divide each side by 4 :

       52 = Mom's age

Daughter's age = 67 - Mom's age = 67 - 52 = 15

If 2 is added to seven times a number and equals 8 more than six times a number what is the number

Answers

Seven times a number is 7x; 6 times a number is 6x and then solve7x+2=6x+8X+2=8X=6
Your word equation turned into an operation would be: 2+7n=8+6n. To complete this equation you have to balance it out so only n would be put on one side. So, try subracting 6n on both sides so it can be on the same side as 7n:2+7n-6n=8+6n-6n.Therefore the 6n on the right side has now switched over to the left. Then, you need to switch the 2 onto the right side by subtracting it on both sides as well:2+7n-6n-2=8-2The 2 has now been switched. After, subtract 7n-6n=1n, and 8-2=6. The equation then becomes:1n=6.To isolate n from 1, divide 1n by 1 and 6 by 1. Your equation afterwards should be: n=6/1, or as simplified: n=6.

Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins to solve the equation for h but runs out of time. Her partial work is shown below: p = 4l + 4w + 4h = l + w + h h = –

Answers

Answer: ( l + w)

your welcome


Answer:

Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins to solve the equation for h but runs out of time. Her partial work is shown below: p = 4l + 4w + 4h = l + w + h h =             l+w

Over a two-hour time period, a snail moved 108 inches. How far is this in yards?

Answers

In two-hour time period, a snail moved 3 yards.

Given that, over a two-hour time period, a snail moved 108 inches.

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

We know that, 1 yard = 36 inches

Here, in yards = 108/36

= 3 yards

Therefore, in two-hour time period, a snail moved 3 yards.

To learn more about the metric conversion visit:

brainly.com/question/21244256.

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the snail moved 108 inches
108/36=3 yards
as 1 yard=36 in