How many vertices does a hexagonal prism have?

Answers

Answer 1
Answer: It has 8 faces but 12 vertices

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Which value of x makes this equation true -5(x - 20) = 35

Answers

The value of \(x\) that makes the equation true is \(x = 13\).

To find the value of \(x\) that makes the equation \(-5(x - 20) = 35\) true, you need to simplify the equation and solve for \(x\). Let's break down the steps:

1. **Distribute the -5 on the left side:**

\[-5(x - 20) = 35\]

\[-5x + 100 = 35\]

2. **Move the constant term (100) to the right side by subtracting 100 from both sides:**

\[-5x = -65\]

3. **Finally, divide both sides by -5 to solve for \(x\):**

\[x = (-65)/(-5)\]

\[x = 13\]

To verify, substitute \(x = 13\) back into the original equation:

\[-5(13 - 20) = 35\]

\[-5(-7) = 35\]

\[35 = 35\]

The equation is true when \(x = 13\).

For more such questions on equation

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Answer:

x=13

Step-by-step explanation:

Divide both sides by -5 then solve the equation for x

Q1: A group of 50 biomedical students recorded their pulses rates by counting the number of beats for 60 seconds. (15)80

48

88

70

84

82

66

84

82

64

44

72

90

70

86

104

58

84

72

60

90

108

62

52

72

86

66

104

78

82

96

54

68

76

72

88

102

74

68

74

78

66

72

90

62

100

92

84

76

72



(a) Construct frequency distribution.

(b) Compute mode, median and mean of the frequency distribution.

(c) The lower and upper quartile of the frequency distribution.

Answers

Answer:

The answers are in the explanation.

Step-by-step explanation:

a)

X1 -Absolute frecuency -cumulative absolute frequency -Relative frecuency

44                 1                                      1                                              0.021

48                 1                                     2                                              0.021

52                 1                                     3                                              0.021

54                 1                                     4                                              0.021

58                 1                                     5                                              0.021

60                 1                                     6                                              0.021

62                 2                                    7                                              0.042

64                 1                                     8                                              0.021

66                 3                                    12                                              0.063

68                 2                                    14                                             0.042

70                 2                                    16                                             0.042

72                 6                                    22                                              0.126

74                 2                                    24                                             0.042

76                 2                                    26                                             0.042

78                 2                                    28                                             0.042

80                 1                                     29                                             0.021

82                 3                                    32                                              0.063

84                 4                                    36                                             0.084

86                 2                                    38                                             0.042

88                 2                                    40                                             0.042

90                 3                                    43                                              0.063

92                 1                                     44                                             0.021

96                 1                                     45                                             0.021

100                 1                                     46                                             0.021

102                 1                                     47                                             0.021

104                 2                                    49                                             0.042

108                 1                                     50                                             0.021

Total:             50                                   50                                                1

  • b) Mean: is the number average = 3806/48 = 78.12
  • Median: is the number or average number of half = 76
  • Mode: Is the number that appears most frequently = 72

  • c) Lower quartile: 67
  • Upper quartile: 84

The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that he must stop at the first signal is 0.45, the analogous probability for the second signal is 0.5, and the probability that he must stop at at least one of the two signals is 0.9.Required:
a. What is the probability that he must stop at both signals?
b. What is the probability that he must stop at the first signal but not at the second one?
c. What is the probability that he must stop at exactly one signal?

Answers

Answer: a. 0.05

b. 0.40

c. 0.85

Step-by-step explanation:

Let F= Event that a certain motorist must stop at the first signal.

S =  Event that a certain motorist must stop at the second signal.

As per given,

P(F) = 0.45 , P(S) = 0.5 and P(F or S) = 0.9

a. Using general probability formula:

P(F and S) =P(F) + P(S)-  P(F or S)

= 0.45+0.5-0.9

= 0.05

∴ the probability that he must stop at both signals = 0.05

b. Required probability = P(F but (not s)) = P(F) - P(F and S)

= 0.45-0.05= 0.40

∴ the probability that he must stop at the first signal but not at the second one =0.40

c. Required probability = P(exactly one)= P(F or S) - P(F and S)

= 0.9-0.05

= 0.85

∴   the probability that he must stop at exactly one signal = 0.85

Final answer:

The probability of stopping at both signals is 0.225, the probability of stopping at the first one but not the second one is 0.225. The probability of stopping at exactly one signal is 0.675.

Explanation:

The probability theory can be used to answer these questions. The probabilities of stopping at various traffic signals can be calculated using some assumptions about the independence of the events.

  1. The probability of the motorist having to stop at both signals can be found by multiplying the individual probabilities, assuming that these are independent events. So, P(stop at both signals) = P(stop at first signal) * P(stop at second signal) = 0.45 * 0.5 = 0.225.
  2. The probability of him stopping at the first signal but not at the second one is again found by multiplying the probability of stopping at the first by the probability of not having to stop at the second. Therefore, P(stop at first, not at second) = 0.45 * (1 - 0.5) = 0.225.
  3. To find the probability that the driver must stop at exactly one signal, we can subtract the probability of stopping at both signals from the probability of stopping at least one signal. So, P(stop at one signal) = P(stop at at least one signal) - P(stop at both signals) = 0.9 - 0.225 = 0.675.

Learn more about Probability here:

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What is the y-intercept of function f?A. 1

B. -1

C. -2

D. 5

Answers

Answer:

1

Step-by-step explanation:

The y intercept is when x =0

We need to use the second equation

-x+1  since -2 < 0 <3

0+1

The y intercept is 1

Eric ran 3 miles in 20 minutes. what is eric’s speed?

Answers

Answer:

Step-by-step explanation:

speed=distance/time

20 minutes=1/3 hours

=3*3/1

=1miles/hour

Top answer is wrong it is
9miles per hour since 20 minute / 60 hour = 0.333333
D=s/t
D=3/0.33333
D=9 miles per second

Need help please show how you did it.

Answers

Answer:

(0, 1).

Method 1 (Substitution):

Substituting our two y's, we get the following:

x^2 + 5x + 1 = x^2 + 2x + 1 \Rightarrow 3x = 0 \Rightarrow x = 0

Thus, the only set of solutions is (0, 1). A quick sketch (either by hand or on Desmos) can confirm this.

Method 2 (Elimination):

We have two equations. We'll let the top one be equation 1 and the bottom one be equation 2. Eliminating as many variables as we can, we subtract (2) from (1) to get:

0 = 3x => x = 0.

So the only set of solutions is (0, 1).

Method 3 (Gaussian elimination):

We can place this in an augmented matrix and row reduce.

\left[\begin{array}{cccc}1&5&1 & 1\n1&2&1 & 1\end{array}\right]

Row reducing this gives us:

\left[\begin{array}{cccc}1&5&1 & 1\n0&3&0 & 0\end{array}\right]

This tells us that the only solution for x is x = 0 (since we read this as "3x = 0") and thus, the only solution we get is (0, 1).