Answer:
4/8
Step-by-step explanation:
Answer:
The student can proceed with the calculation of the confidence interval for the difference in population proportions. This is because, from the data she has, 3/4 of the Business students admitted to cheating while 1/2 of the Nursing students admitted to cheating also.
This is above the average number of students in her given sample size which is valid for extrapolation to the College Majors being investigated.
Step-by-step explanation:
Answer:
Around 9.57 minutes to edit
Step-by-step explanation:
Do 28 divided by 6 to get around 4.7. Then do 45 divided by 4.7 to get the answer.
Answer:
L=10cm , W=30cm
Step-by-step explanation:
First use the given that W=10+2*L
Use P=2W+2L=80, substitute W in the perimeter formula
2(10+2L)+2L=80 and solve for L,
20+4L+2L=80 isolate variable L and combine like terms,
6L=80-20,
L=10, so W=10+2*10=10+20=30
Answer:
The lowest score eligible for an award is 92.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award
The lowest score is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975. So X when Z = 1.96. Then
The lowest score eligible for an award is 92.
V=96ft., h=8ft
b. Segment CB is a hypotenuse.
c. Segment CA is shorter than segment BA.
d. Angle C is congruent to itself.
Answer:
The correct answer is option A.
Step-by-step explanation:
For the given triangles to be similar the segment AD must be an altitude of ΔABC.
We can provide a theorem for the same:
If we draw an altitude from the right angle of any right triangle, then the two triangles formed are similar to the original triangle.
Also all the three triangles are similar to each other.
Like here, in the triangle ABC, we draw an altitude from A to the side BC, thus forming 2 triangles; ΔDBA and ΔDAC. These both will be similar to ΔABC.
So, by the theorem it is proven that ΔABC is similar to ΔDBA.
Therefore, option A is correct.