Three hundred high school seniors were surveyed about their intended college majors. The results are displayed in the Venn Diagram below: A Venn Diagram titled College Majors with two circles labeled Math and Science. In the math portion is 120. In the intersection is blank. In the Science portion is 50. The area outside the two circles is labeled 100.

If a student is randomly selected from the group, what is the probability that they are majoring in both math and science? Round your answer to the nearest whole percent.

Answers

Answer 1

Answer: I see what's going on, we have to find the number of students in the intersection. Math is 120, Science is 50, neither is 100. Add all of these together, 120 + 50 + 100 = 270, then subtract from 300, 300-270 = 30
Now, we divide 30/300 which gives .1, move the decimal over 2 places to the right and that makes it 10%

Answer 2

Answer:

Answer: $(1)/(10)$

Step-by-step explanation:

Since, The total number of student = 300

Out of which,

The number of students who are only in Maths = 120

And, The number of students who are only in Science = 50

While, the students who are not from any subject = 100

Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None

= 300 - 120 - 50 - 100

= 30

That is, there are 30 students who are both from science and maths,

Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10

Related Questions

There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. The ratio of the number of sophomore to all students is 1:2. What is the ratio of the number of freshman to sophomore?
I need help pleasee
What is the answer to ... Calculate the length of the circumference of a circle with a diameter of 9.2cm.
Calculate f(4) for each function below
What polynomial when divided by 2y^5 yields 4y^2-2y+9 as a quotient?

Line m has a y-intercept of c and a slope of q/p, where p > 0, q > 0, and p ≠ q.What is the slope of a line that is perpendicular to line m?

Answers

Answer:

-p/q

Step-by-step explanation:

m1 = Slope of line 1 (Line m) = q/p

m2 = Slope of line 2

Since the lines are perpendicular,

m1•m2 = -1

Therefore,

m2 = -1/m1

m2 = -1/(q/p)

m2= -p/q

Please mark brainliest,

Thanks.

there are three people who work full-time and are to work together on a project but their total time on the project is to be equivalent to that of only one person working full-time if one of the people is budgeted for one-half of his time to the project and a second person for one third of her time what part of the third workers time should be budgeted to this project

Answers

This would be:
$1 - (1)/(2) - (1)/(3)$

Using common denominator of 6:
$(6)/(6)- (3)/(6)- (2)/(6) = (1)/(6)$

They should use $(1)/(6)$ of their time.

For her semester project, an art student was required to complete an oil painting that was at least 5 square feet in area. If the student wanted to make a painting that was 3 3/4feet wide, what is the minimum height (in feet) that it could be?

Answers

The area of the figure would have to be:
Height × Width

The minimum area would be:
5×5=25 square ft.

To find the minimum height,we devide the area by it's width.

If the painting is 3 3/4 feet wide,the minimum height would have to be:
25÷3 3/4
=25/3×3/4
=25/4 or 6 1/4 ft.

Thus the answer would be:25/4 or 6 1/4 ft.

Hope it helps!

The minimum height would be roughly 1.67 feet.

-18=d+4 plZ hurry thank you so much have a great day

Answers

Answer:

d = - 22

Step-by-step explanation:

- 18 = d + 4 ( subtract 4 from both sides )

- 22 = d

4. Let f(x)=-2x+7 and g(x)=-6x+3. Find f×g and state its domainA. 12x^2-48x+21;all real numbers
B. -14x^2+36x-18;all real numbers except x=7
C. -14x^2+36x-18;all real numbers
D. 12x^2-48x+21;all real numbers except x=1

Answers

I hope this helps you

(f.g) (x)=(-2x+7)(-6x+3 )

(f.g)(x)=12x^2-6x-42x+21

(f.g)(x)=12x^2-48x+21

A

the answer is A ...

Evaluate |x + y|, for x = 8 and y = -15.

Answers

First, we substitute the numbers to the corresponding variables.

|(8) + (-15)|

And we change the plus sign since we’re just basically subtracting.

|8 - 15|

|-7|

Now to do absolute values, we must remember that it will always equal a positive unless there is a negative sign outside of the | |.

So the final answer will be 7.

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