4/3v =12

Simplify your answer as much as possible.

Answers

Answer 1
Answer: \frac { 4 }{ 3 } v=12\n \n \frac { 3 }{ 4 } \cdot \frac { 4 }{ 3 } v=\frac { 3 }{ 4 } \cdot 12\n \n v=\frac { 36 }{ 4 } \n \n v=9
Answer 2
Answer: 4/3v = 12
3/4 × 4/3v = 12 × 3/4
v = 9


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⚠️I NEED THE ANSWER RIGHT NOW!! I WILL GIVE BRAINLIST!⚠️Subtract 5/6−(-4/9).1 5/187/18-7/18-1 5/18
Which are properties of rotations? Check all that apply.

Please need help!!!!

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it's is true because 4 and 5are closer

Need help please....

Answers

To solve this or to simplify it simply divide both the top and bottom terms. In the quotient.

By dividing each term with the correct similar variable, you can simplify the expression.

2x - 3y would be the final answer.







Which pair of undefined terms is used to define the term parallel lines?point and line
plane and line
point and ray
ray and line

Answers

Answer:

The correct answer for this is : A. Point and Line

Step-by-step explanation:

The lines are said to be parallel to each other if they do not intersect each other at any point. So, for any number of lines to be parallel we must have lines and no intersection points between them then only we can say the given number of lines are parallel to each other

So, the terms which are used to explain the term parallel lines here are : line and the point.

And the both terms point and a line are undefined in the geometry.

Hence, the correct answer for this is : A. Point and Line

The pair of undefined terms are used to define the term parallel lines are point and line. Option A.  This is further explained below.

What are parallel lines?

Generally,  parallel lines are simply defined as Two lines in the same plane that are always exactly the same distance apart and are said to be parallel.

In conclusion, If there is no point at which the lines meet, then we say that they are parallel to one another. Therefore, in order to state that a particular set of lines is a set of parallel lines, we must first establish that there is a set of lines with no junction points.

Read more about  parallel lines

brainly.com/question/16701300

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Tabitha wants to hang a painting in a gallery. The painting and frame must have an area of 58 square feet. The painting is 7 feet wide by 8 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?

Answers

The quadratic equation would be;
x2+15x-2=0

Working:
Assuming the area around the painting i.e the frame, has a uniform thickness, then;
Length of painting and frame = 8+x
Breadth of painting and frame= 7+x

The area from above step gives;
 A= LxW
A= (8+x)(7+x)
On expanding, 56+8x+7x+x2
On simplifying,
56+15x+x2. This should be equal to 58.
58=x2+15x+56
Taking 58 to the other side,
x2+15x-2=0

Solve: −7/3a+4=47/3

What is A
I will give extra points to who gets this right also will give brainliest

Answers

Answer:

a= -5

Step-by-step explanation

PEMDAS

1. Complete the tables of values below for graphing the secant and cotangent functions. You can type “U” for an undefined value. Use exact values with fractions and square roots, not the decimal approximations. For example, use 3/2 rather than 0.866 (pictures attached) 2. Graph the secant graph for 0 ≤ x ≤ 2π. Graph the cotangent graph for 0 ≤ x ≤ 2π. (don't need these pictures I have them)


3. Indicate whether each of the three reciprocal functions (cosecant, secant, and cotangent) is a periodic function. If so, state the period of each.


4. List the domain and range for the secant and cotangent functions. (Use "pi" for π.)


5. Compare the graphs of the cosecant and secant functions. How are they different? How are they similar?

Answers

Step-by-step explanation:

1. All the trigonometric values can be found using the unit circle.  See attached table.

2. Graph:

desmos.com/calculator/10n7yrm3tm

3. All trig functions are periodic functions.  The period of secant and cosecant is 2π.  The period of cotangent is π.

4. Using the table from step 1 and the graph from step 2, secant has a domain of x ≠ pi/2, 3pi/2 and a range of x ≤ -1, x ≥ 1.  Cotangent has a domain of x ≠ 0, pi, 2pi and a range of -∞ < x < ∞.

5. Graph:

desmos.com/calculator/tldiqt7qra

Cosecant has the same graph as secant shifted π/2 to the right.  So they have different domains, but the same range.