Given:
Sample no. of events,
Sample size,
Now,
The sample proportion will be:
→
The significance level will be:
Form the z-table,
The critical value,
Now,
The standard error will be:
=
=
and,
The margin of error,
→
Now,
The lower limit will be:
=
=
The upper limit will be:
=
=
hence,
The CI is "(0.6744, 0.748)". Thus the response above is right.
Learn more about confidence interval here:
Answer:
CI = (0.674, 0.748)
Step-by-step explanation:
The confidence interval of a proportion is:
CI = p ± SE × CV,
where p is the proportion, SE is the standard error, and CV is the critical value (either a t-score or a z-score).
We already know the proportion:
p = 293/412
p = 0.711
But we need to find the standard error and the critical value.
The standard error is:
SE = √(p (1 − p) / n)
SE = √(0.711 × (1 − 0.711) / 412)
SE = 0.0223
To find the critical value, we must first find the alpha level and the degrees of freedom.
The alpha level for a 90% confidence interval is:
α = (1 − 0.90) / 2 = 0.05
The degrees of freedom is one less than the sample size:
df = 412 − 1 = 411
Since df > 30, we can approximate this with a normal distribution.
If we look up the alpha level in a z score table or with a calculator, we find the z-score is 1.645. That's our critical value. CV = 1.645.
Now we can find the confidence interval:
CI = 0.711 ± 0.0223 * 1.645
CI = 0.711 ± 0.0367
CI = (0.674, 0.748)
So we are 90% confident that the proportion of adults connected to the internet from home is between 0.674 and 0.748.
Answer:
the answer is 4 3/4 i think
Step-by-step explanation:
Hey there!
The correct answer is 4 3/4 inches
The lines on the ruler (in between each inch) represent the fractions of the inch. The first line would be 1/4 the second line is 2/4 or 1/2 and the third line is 3/4
Hope this helps you!
God bless ❤️
Brainliest would be appreciated
xXxGolferGirlxXx
A 12 cm
B 10 cm
C 9.cm
D 6 cm
Answer:
The number of students who actually went for the skiing is 0.75 times the total number of students .
Step-by-step explanation:
Given as :
Students were surveyed about their wither break plans
The percentage of students who did not go for skiing = 25 %
So, The percentage of students who did not go for skiing =100 % - 25 % = 75%
Let The total number of students = x
So, The number of students actually went for the skiing = 75% of the total number of students
I.e The number of students actually went for the skiing = × x
Or, The number of students actually went for the skiing = 0.75× x
∴ The number of students actually went for the skiing = 0.75 x
Hence The number of students who actually went for the skiing is 0.75 times the total number of students . Answer
Answer:x=2 x=6
Step-by-step explanation: