A relationship can be damaged by?

Answers

Answer 1
Answer:

Answer:not meeting expectations

Explanation:

Answer 2
Answer: fights and a non sturdy relationship and fights happen a lot

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An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to the left with a velocity of 7.2m/s. If the collision is elastic, what is the speed and direction of each car after the collision?

Answers

The final velocity of car 1 is -0.36 m/s to the left, and the final velocity of car 2 is 6.69 m/s to the right.

What is the conservation of momentum?

The conservation of momentum is a fundamental principle in physics that states that the total momentum of a closed system remains constant if no external forces act on the system. In other words, the total momentum of a system before a collision or interaction is equal to the total momentum of the system after the collision or interaction, as long as there are no external forces acting on the system.

Mathematically, we can express the conservation of momentum as follows:

P_initial = P_final

Where:

P_initial is the total momentum of the system before the interaction or collision

P_final is the total momentum of the system after the interaction or collision

Momentum is a vector quantity, which means it has both magnitude and direction. Therefore, the conservation of momentum applies separately in each direction. For example, if two objects collide and move in different directions after the collision, the momentum of one object in the positive direction will be equal and opposite to the momentum of the other object in the negative direction, so the total momentum of the system is conserved.

The conservation of momentum is an important principle in many areas of physics, such as mechanics, electromagnetism, and quantum mechanics. It is used to analyze collisions, explosions, rocket propulsion, and other physical phenomena involving the transfer of momentum.

Here in the Question,

To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy, since the collision is elastic. According to these laws, the total momentum and total kinetic energy before and after the collision must be equal. We can write this as:

Total initial momentum = Total final momentum

and

Total initial kinetic energy = Total final kinetic energy

Let's first find the initial momentum of the system:

P_initial = m1v1 + m2v2

= (0.75 kg)(8.5 m/s) + (0.65 kg)(-7.2 m/s) (since car 2 is moving to the left, its velocity is negative)

= 1.225 kg m/s to the right

According to the law of conservation of momentum, the total momentum of the system must be conserved after the collision. Therefore, the final momentum must also be 1.225 kg m/s to the right.

Let's now find the initial and final kinetic energies of the system:

KE_initial = (1/2)m1v1^2 + (1/2)m2v2^2

= (1/2)(0.75 kg)(8.5 m/s)^2 + (1/2)(0.65 kg)(-7.2 m/s)^2

= 26.228 J

According to the law of conservation of kinetic energy, the total kinetic energy of the system must also be conserved after the collision. Therefore, the final kinetic energy must also be 26.228 J.

Let's now find the final velocities of the two cars. We can use the momentum conservation equation to set up a system of two equations (one for the conservation of momentum and one for the conservation of kinetic energy) with two unknowns (the final velocities of the two cars). Solving this system of equations, we get:

v1f = (m1-m2)/(m1+m2)v1 + 2m2/(m1+m2)v2

= (0.75 kg - 0.65 kg)/(0.75 kg + 0.65 kg)8.5 m/s + 20.65 kg/(0.75 kg + 0.65 kg)(-7.2 m/s)

= -0.36 m/s to the left

v2f = 2*m1/(m1+m2)*v1 - (m1-m2)/(m1+m2)v2

= 20.75 kg/(0.75 kg + 0.65 kg)8.5 m/s - (0.75 kg - 0.65 kg)/(0.75 kg + 0.65 kg)(-7.2 m/s)

= 6.69 m/s to the right

Therefore, the final velocity of car 1 is -0.36 m/s to the left, and the final velocity of car 2 is 6.69 m/s to the right.

To learn more about momentum and  impulse equations click:

brainly.com/question/30101966

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We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)

An 880 kg cannon at rest fires a 12.4 kg cannonball forward at 540 m/s. What is the recoil velocity of the cannon? (Unit m/s)

Answers

Answer:

The recoil velocity vector of the cannon is (7.609,0,0)(m)/(s)

Explanation:

We can solve this problem by applying the Momentum Conservation Principle.

The principle of conservation of momentum states that when you have an isolated system with no external forces, we can use the following equation to calculate the final velocity of one object.

m1.v1=m2.v2 (I)

Where ''m1'' and ''v1'' are the mass and velocity of the first object.

And where ''m2'' and ''v2'' are the mass and velocity of the second object.

The momentum is a vectorial magnitude.

If we use the equation (I) with the data given :

(880kg).v1=(12.4kg).(540(m)/(s))

v1=7.609(m)/(s)

If we considered as negative the sense of the velocity vector from the cannonball, the cannon's velocity vector will have the same direction but opposite sense that the cannonball's velocity vector (It will be positive).

We can give it a vectorial character like this :

v1=(7.609,0,0)(m)/(s)

The velocity vector will be entirely in the x-axis.

Answer:

7.61 m/s backwards

Explanation:

Initial momentum = final momentum

0 = (880 kg) v + (12.4 kg) (540 m/s)

v = -7.61 m/s

The cannon's recoil is 7.61 m/s backwards.

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Answers

Answer:

Stimulants are a group of drugs that result in increased activity in the body. Sometimes referred to as “uppers,” these drugs are frequently abused due to their performance-enhancing and euphoric effects. Generally, those who abuse stimulants experience heightened energy levels and enhanced focus.

Stimulants speed up mental and physical processes, which can produce desirable effects in the short-term by increasing levels of dopamine in the brain. While users may feel great due to the short-term effects of stimulants, long-term abuse of these drugs can have significant consequences, which is why it is so important for those who abuse the drugs to get help as quickly as possible.

Explanation:

hope this works

I love how they said random stuff and than a response about drugs

State two factors which affect moment of force

Answers

Two factors that affect the moment of force are the magnitude of the force applied and the distance from the axis of rotation at which the force is applied.

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Device that measures electric current

Answers

This device is called an ammeter.

Enter the expression 2cos2(θ)−1, where θ is the lowercase Greek letter theta.

Answers

2cos2(θ)−1 = 0
2cos2(θ)=1
cos2(θ)=1/2
2θ=arc cos1/2
2θ=60 degrees
θ=30 degrees