Find the x-intercept of the parabola with vertex (1,-13) and y-intercept (0,-11).

Answers

Answer 1
Answer: Standard form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex
using given coordinates of vertex:
y=A(x-1)^2-13
using given coordinates of y-intercept:
-11=A(0-1)^2-13
A=2
Equation of parabola: y=2(x-1)^2-13
x-intercepts

set y=0
0=2(x-1)^2-13
2(x-1)^2=13
(x-1)^2=13/2
x-1=±√(13/2)
x=1±√(13
Answer 2
Answer: 1. find equation

general solutions are:
y = a x^(2) +bx +c \n \n (dy)/(dx) = 2ax +b

for P(0,-11)

-11 = 0a + 0b +c ⇒c = -11

for p(1,-13)
-13 = 1a + 1b -11 \n a+b = -2

and

0 = 2a + b \n b = -2a

solve for a and b:
a - 2a = -2 \n a = 2 \n b = -4

the total equation is now:

y = 2 x^(2) -4x -11

To find the x-intercept set y=0 and solve for x

0 = 2 x^(2) -4x-11

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A certain species of tree grows an average of 3.8 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 5 meters tall.

Answers

The answer is f(x) = 500 + 3.8x

The number of weeks is x. So, weekly, the tree grows 3.8x. 
If the measurements of the growth begin when the tree started to grow, the equation would be: f(x) = 3.8x.
But, the measurements begin when the tree is 5 m tall. Since 1 m is 100 cm, this means that 5 m is 500 cm. Thus, the equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 5 meters tall is:
f(x) = 500 + 3.8x

Answer:

n=500+8(n-1)

DO NOT FORGET that the tree is already 5 meters tall on the FIRST WEEK, not the 0th week. So, f(x)=500+3.8x is incorrect.

(For example, on the second week the tree should be 503.8 meters tall. But if you plug 2 in f(x)=500+3.8x, you would get 507.6, which is the height of the tree on the third week.)

The sum of the roots of the equation (1/2)x^2-(5/4)x-3=0

a.5/2
b.2
c.1/2

Answers

(1/2)x² - (5/4)x - 3 = 0

0.5x² - 1.25x - 3 = 0

Comparing to the quadratic function, ax² + bx + c = 0,    
a = 0.5,  b = -1.2,  c = -3.

Sum of roots = -b/a   =    -(-1.25)/0.5 =    1.25/0.5 = 2.5

2.5 = 5/2  Option (a)
A)5/2 is the answer.

PRECAL worksheet NEED HELP ASAP. 100 points

Please please help me.

Answers

Step-by-step explanation:

Q1:

• Reflection about the X-axis.

• g(x) = -f(x).

Q2:

• Horizontal translation 1 unit to the right.

• g(x) = f(x-1).

Q3:

• Scaling by 2 times in the vertical direction.

• g(x) = 2f(x).

Solve the equation. Show your work.

1/a =6/18

Answers

 
1          6                    
---    =  ---   
 a        18

- simplify 6/18, which should be 1/3. therefore, a = 3.

The diagram shows a patio in the shape of a rectangle.The patio is 3.6m long and 3m wide.

Mathew is going to cover the patio with paving slabs. Each paving slab is a square of side 60cm.

Mathew buys 32 of the paving slabs.

A) Does Mathew buy enough paving slabs to cover the patio?

The paving slabs cost £8.63 each

B) Work out the total cost of the 32 paving slabs.

Answers

if Mathew has bought 32 slabs , he has enough paving slabs to cover the patio and  £276.16 is the total cost of the 32 paving slabs.

What is a Rectangle ?

A rectangle is a polygon with 4 sides , in which opposite sides are parallel and equal .

It is given that the patio has  length of 3.6 m and width of 3 m

Each paving slab is a square having side 60 cm or .6 m

Area of a rectangle is given by

length * width

3.6*3

10.8 m²

Area = 10.8 m²

Area of a slab = 0.6 *0.6 = 0.36 m²

No. of slabs needed = n

10.8 = 0.36* n

n = 30 slabs

So if Mathew has bought 32 slabs , he has enough paving slabs to cover the patio.

If the paving cost costs £8.63

The total cost for 32 slabs will be 32 * £8.63

= £276.16

To know more about Rectangle

brainly.com/question/15019502

#SPJ2

A-pario\ area\n A=3.6*3=10.8m^2\n A_2-slab\ area\n A_2=60cm*60cm=3600cm^2=0.36m^2\n 0.36m^2*32=11.52>10.8\n 32\ is\ enough\n\n 8.63*32=276.16-total\ cost

Find if 2700=2200(1+r)ˆ5 

( ˆ5 is the exponent for 5 )

Answers

2700=2200(1+r)^5 \ /:2200\n\n(1+r)^5= (27)/(22) \n\n1+r= \sqrt[5]{(27)/(22) } \n\nr=\sqrt[5]{(27)/(22) } -1