II
III
IV
In which quadrant is the number –14 – 5i located on the complex plane? I II III IV
Answer:
III
Step-by-step explanation:
go 14 left and 5 down, and you're in the third quadrant
Answer:
III (Third quadrant)
Step-by-step explanation:
Okay, in terms of complex numbers, the x axis is the imaginary scale while the y axis is the real scale. And this works just like a normal x and y axis! We can break down -14-5i into -5i and -14, and -5i is the imaginary number on the x axis, so we move five units to the left from the origin. -14 is the real number, so we then move down 14 units, and we end up with a coordinate that is in the III, or third, quadrant. Hope this helps! :)
.
•
This number,
x
, is
3
_
4
of another number, which is represented by
y
.
•
The number represented by
y
equals
1
_
3
of another number, which is
represented by
z
.
•
The number represented by
z
is a number from 140 to 151.
•
The numbers represented by
x
,
y
, and
z
are whole numbers.
(a)
What are the values for
x
,
y
, and
z
?
Answer:
72
Step-by-step explanation:
First, divide 32 by 4 to see how many times larger the numbers in the second ratio are than in the first ratio. 32/4=8 This means that the numbers in the second ratio are 8 times larger than in the first
Then, since the second ratio’s numbers are 8 times bigger than those of the first ratio, you can multiply both numbers in the first ratio by 8. The problem already multiplied 4 by 8 for us, which is 32, so all we have to do now is multiply 9 by 8. 9*8=72, which means that 4:9 is equivalent to 32:72
jose is 9 and Sophia is 7 because 32 divided by 2= 16 and 9+7=16 and jose is 2 years older so he has to be nine and she is seven!!! hahaha I figured it out finally