A.
9 × 16 × 10 = f
B.
9 × (16 × 10) = f
C.
(9 × 16) + (9 × 10) = f
D.
(9 + 16) × (9 + 10) = f
3, plus, j, k, plus, k, cubed when j=2j=2j, equals, 2 and k=6k=6k, equals, 6
Answer:
231
This is the answer take it or leave it
6x2 + χ? - 5
8x2 + x
-2x +
Ο
ty
12 is C
15 is A
16 is A
Answer:
The first mechanic $90/hour and the second charged $70/hour
Step-by-step explanation:
Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:
5x+10y = 1150
We also know that together they charged 160/per hour. An equation to express this would be:
x+y = 160
Now we can solve the second equation for x or the first mechanics rate.
x+y = 160
x = 160 - y
Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.
5x+10y=1150 plug in x =160-y
5(160-y)+10y=1150 Distribute
800 -5y+10y = 1150 Combine like terms
800 +5y = 1150 Subtract 800 from both sides
5y = 350 divide by 5
y = 70
So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.
x = 160-y
x = 160-70
x = 90
So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.
The rate per hour for the first mechanic is $105 and for the second mechanic is $85.
This problem is a case of simultaneous equations where we need to determine the rates at which the two mechanics charge. Let's denote the hourly rates of the first and second mechanics as x and y respectively. From the question, we know:
1. x + y = $190 (The sum of the two rates was $190 per hour)
2. 10x + 5y = $1475 (The first mechanic worked for 10 hours and the second mechanic worked for 5 hours, and together they charged a total of $1475)
To solve these equations, you can start by multiplying the first equation by 5 to match the second equation:
5x + 5y = $950
Now, subtract this from the second equation:
10x - 5x = $1475 - $950
5x = $525
Therefore, x ($/hour by the first mechanic) = $525 / 5 = $105
You can now substitute x = $105 into the first equation to get:
$105 + y = $190
Therefore, y ($/hour by the second mechanic) = $190 - $105 = $85
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