The molecular formula of butane is .
Further explanation:
The molecular formula is a chemical formula that depicts the total number and kinds of atoms present in a molecule. For example, molecular formula of carbon dioxide is .
Hydrocarbon is a term for the organic compounds that consist of hydrogen and carbon only.
Types of hydrocarbons:
1. Saturated hydrocarbons
The simplest hydrocarbons that are composed of only single bonds are called saturated hydrocarbons. These hydrocarbons have the general formula of , where n is the number of carbon atoms. These hydrocarbons have suffix “ane” in their names. Examples of such hydrocarbons are methane, hexane, and propane.
2. Unsaturated hydrocarbons
These have one or more multiple bonds in them. These hydrocarbons have suffix “ene” or “yne”, depending on whether there is a double or triple bond between them. Hydrocarbons comprising of double bonds are called alkenes and those having triple bonds are called alkynes.
The name of butane includes the suffix “ane”. This implies it is a saturated hydrocarbon and contains only single bonds in it. The prefix “but” indicates the presence of four carbon atoms in this molecule.
Substitute 4 for n in the general formula of alkane to find out the formula of butane.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Stoichiometry of formulas and equations
Keywords: molecular formula, butane, C4H10, 4, ane, ene, yne, alkane, alkyne, alkene, saturated hydrocarbon, unsaturated hydrocarbon.
Answer:
2 hydrogen atoms bonded with 1 oxygen atom
Explanation:
In the compound , the number 2 after the H means that there are two atoms in the preceding letter (element), and since there are no numbers ofter the O, that means there is only 1 atom.
Answer:
Explanation:
At same temperature and same number of moles, Using Boyle's law
Given ,
V₁ = 10 mL
V₂ = 20 mL
P₁ = 5.85 kPa
P₂ = ?
Using above equation as:
a. distillation
b. chromatography
c. filtration
d. crystallization
Answer:
c.filtration is the answer
The type of stoichiometric calculation that does not require the use of the molar mass is a calculation involving molar or stoichiometric ratios which are derived directly from the coefficients in a balanced chemical equation.
In stoichiometry, there are several types of calculations that can be performed. However, the type of stoichiometric calculation that does not require the use of the molar mass is the calculation involving the molar ratio, or stoichiometric ratio. This refers to the ratio of coefficients in a balanced chemical equation, which we use to determine the relative amounts of each substance involved in a chemical reaction.
An example of this is a balanced equation for the formation of water: H2 + 0.5O2 -> H2O. In this equation, the molar or stoichiometric ratio of hydrogen (H2) to oxygen (O2) to water (H2O) is 2:1:2. If we are given the number of moles of one substance, we can use this molar ratio to find the number of moles of any other substance in the equation, without needing to know their molar masses. This constitutes a stoichiometric calculation without the need for molar mass.
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Answer:
pure substance
Explanation:
i just did on edgen