Explanation:
It is known that formula for area of a sphere is as follows.
A =
=
= 3.14
= (27 + 273.15) K = 300.15 K
T = (77 + 273.15) K = 350.15 K
Formula to calculate the net charge is as follows.
Q =
where, e = emissivity = 0.85
s = stefan-boltzmann constant =
A = surface area
Hence, putting the given values into the above formula as follows.
Q =
=
= 1046.63 W
Therefore, we can conclude that the net flow of energy transferred to the environment in 1 second is 1046.63 W.
Answer : The final temperature of the solution in the calorimeter is,
Explanation :
First we have to calculate the heat produced.
where,
= enthalpy change = -44.5 kJ/mol
q = heat released = ?
m = mass of = 1.52 g
Molar mass of = 40 g/mol
Now put all the given values in the above formula, we get:
Now we have to calculate the final temperature of solution in the calorimeter.
where,
q = heat produced = 1.691 kJ = 1691 J
m = mass of solution = 1.52 + 35.5 = 37.02 g
c = specific heat capacity of water =
= initial temperature =
= final temperature = ?
Now put all the given values in the above formula, we get:
Thus, the final temperature of the solution in the calorimeter is,
Answer: The mass of produced is, 15.2 grams.
Explanation : Given,
Mass of = 30.0 g
Mass of = 10.0 g
Molar mass of = 100 g/mol
Molar mass of = 36.5 g/mol
First we have to calculate the moles of and .
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.274 moles of react with moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 1 mole of
So, 0.274 mole of react to give mole of
Now we have to calculate the mass of
Molar mass of = 110.98 g/mole
Therefore, the mass of produced is, 15.2 grams.
b. 4
c. 8
d. 16
There are eight hydrogen atoms in the following molecule of ammonium sulfide. Thus, the correct option for this question is C.
A molecule may be defined as a cluster of atoms that are significantly bonded together in order to represent the smallest basic unit of a chemical compound that can involve in a chemical reaction.
According to this question, the correct representation of ammonium sulfide is , where the number of the hydrogen atoms is equal to 4 × 2 = 8. Apart from this, the number of nitrogen atoms is 2. While the number of sulfur atoms is only 1.
Therefore, there are eight hydrogen atoms in the following molecule of ammonium sulfide. Thus, the correct option for this question is C.
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60 ml of a 0.40 m solution of h2so4 is used to neutralize 0.3 m magnesium hydroxide solution, the volume of NaOH required to neutralize the given amount of Mg(OH)2 is 160 ml.
To answer this question, we need to use the concept of stoichiometry. Stoichiometry is the calculation of the quantities of reactants and products in a chemical reaction. The balanced chemical equation for the neutralization reaction between sulfuricacid (H2SO4) and magnesium hydroxide (Mg(OH)2) is:
H2SO4 + Mg(OH)2 → MgSO4 + 2H2O
From the equation, we can see that one mole of H2SO4 reacts with one mole of Mg(OH)2. Therefore, the number of moles of Mg(OH)2 in 60 ml of 0.3 m solution is:
moles of Mg(OH)2 = concentration x volume = 0.3 x (60/1000) = 0.018 moles
Since one mole of Mg(OH)2 requires one mole of NaOH to neutralize it, we need 0.018 moles of NaOH. The concentration of the NaOH solution is not given, so we cannot directly calculate the volume of NaOH required. However, we can use the concentration and volume of the H2SO4 solution to find the number of moles of H2SO4 used in the neutralization reaction:
moles of H2SO4 = concentration x volume = 0.40 x (60/1000) = 0.024 moles
From the balanced equation, we know that one mole of H2SO4 reacts with two moles of H2O. Therefore, the number of moles of H2O produced in the reaction is:
moles of H2O = 2 x moles of H2SO4 = 0.048 moles
Since the reaction is neutralization, the same number of moles of H2O and H+ ions are produced. Therefore, the number of moles of H+ ions produced is also 0.048 moles. Each mole of NaOH can neutralize one mole of H+ ions. Therefore, the number of moles of NaOH required is:
moles of NaOH = 0.048 moles
If we assume that the concentration of the NaOH solution is also 0.3 m, then the volume of NaOH required is:
volume of NaOH = moles of NaOH / concentration = 0.048 / 0.3 = 0.16 L = 160 ml
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