Divide. (6a4 + 2a3) ÷ 2a

Answers

Answer 1

Answer: $(6a^4+2a^3):2a=(6a^4+2a^3)/(2a)=(6a^4)/(2a)+(2a^3)/(2a)=3a^3+a^2\n\n\nD:a\neq0$

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The reciprocal of an integer plus the reciprocal of two times the integer plus two equals 2/3 Find the integer.

Answers

$(1)/(x) + (1)/(2x+2)= (2)/(3)\ /\cdot 3x(2x+2) \ \ \ \wedge\ \ \ x \neq 0\ \ \wedge\ \ 2x+2 \neq 0\n \n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x\in R-\{0;-1\}\n \n (1)/(x)\cdot 3x(2x+2) + (1)/(2x+2)\cdot 3x(2x+2)= (2)/(3)\cdot 3x(2x+2)\n \n3(2x+2)+3x=2x(2x+2)\n \n6x+6+3x=4x^2+4x\n \n-4x^2+9x-4x+6=0\n \n-4x^2+5x+6=0\ \ \ \Rightarrow\ \ \Delta=5^2-4\cdot(-4)\cdot6=25+96=121\n \n$

$x_1= (-5- √(121) )/(2\cdot (-4))= (-5-11)/(-8) = (-16)/(-8) =2\ \ \ is\ integer\n \nx_2= (-5+ √(121) )/(2\cdot (-4))= (-5+11)/(-8) = (6)/(-8) =- (3)/(4) \ \ \ is\ not\ the\ integer$

What is the greatest common factor of 2 and 2.5

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The GCF of 2 and 2.5 would be 2

HELP ASAP I NEED THIS DONE.

Answers

26 - add all the sides

Which of the following represents "Twice the abscissa increased by three times the ordinate is ten"?3x + 2y = 10
2y + 3x = 10
2x + 3y = 10

Answers

The abcissa is the name given to the x-coordinate while the ordinate is the other name for the y-coordinate. So, in mathematical terms, "twice the abcissa increased by three times the ordinate is ten" is then described by the third option which is 2x+3y=10.

Answer:

Step-by-step explanation:

Given : Twice the abscissa increased by three times the ordinate is ten.

To find : which equation represent Twice the abscissa increased by three times the ordinate is ten.

Solution : We have abscissa = x.

Ordinate = y.

According to given statement :

Twice the abscissa = 2 * x .

Three times the ordinate = 3 * y.

Twice the abscissa increased by three times the ordinate is ten :

2 * x + 3 * y = 10.

Therefore, This equation 2 * x + 3 * y = 10 is correct.

PLEASE HELP!A company is creating a box without a top from a piece of cardboard, but cutting out square corners with side length x.

Which expression can be used to determine the greatest possible volume of the cardboard box?

A) (x−7)(x−11)x
B) (7−2x)(11−2x)x
C) (11−7x)(11x−7)
D) (7x−11)(7−11x)

Answers

Answer:

Option B

Step-by-step explanation:

Given is a rectangle with width 7 and length 11.

From each corner of the rectangle a square of length x is cut and foled to make a box

Now for the open box we made, height = x

width = rectangle width - 2 times d

= 11-2x

Length = rectangle length-2x

Hence volume of box

=lwh

= (7-2x)(11-2x)x

Answer: B) $(7-2x)(11-2x)x$

Step-by-step explanation:

Given: The length of the cardboard = 11 in.

The width of the cardboard =7 in.

If a box is created without a top from a piece of cardboard, but cutting out square corners with side length x, then the dimensions of box will be:-

Width (w)= $7-2x$