Which of the following items is the most likely to have a mass of 3 mg?A : Cat

B : Pumpkin

C : Ant

D : Piano

Answers

Answer 1

Answer: C.the ant would be the most likely thing to have a mass of three grams.

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The sum of two numbers is 19, and their difference is 55. What are the two numbers?

Answers

Answer:

37 and -18

Step-by-step explanation:

Let one number be x and other y

1 x + 1 y = 19 .............1

1 x -1 y = 55 .............2

Eliminate y

multiply (1)by 1

Multiply (2) by 1

1 x 1 y = 19

1 x + -1 y = 55

Add the two equations

2 x = 74

/ 2

x = 37

plug value of x in (1)

1 x + 1 y = 19

37 + 1 y = 19

1 y = 19 -37

1 y = -18

y = -18

37 and -18

Final answer:

The two numbers, which sum to 19 and have a difference of 55, are 37 and -18.

Explanation:

The sum and difference of two numbers can provide the solution to the problem. In this case, the sum of the two numbers is 19 and the difference is 55. To solve this, we start by setting up two equations based on the problem: x + y = 19 and x - y = 55.

Then we solve these equations simultaneously. We can add the two equations together to eliminate 'y'. This gives us 2x = 74, or x = 37. Substituting x = 37 into the first equation, we get 37 + y = 19, which gives y = -18.

So, the two numbers are 37 and -18.

Learn more about Solving Simultaneous Equations

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Among the 10 most popular sports, men include competition-type sports - pool and billiards, basketball, and softball - whereas women include aerobics, running, hiking, and calisthenics. However, the top recreational activity for men was still the relaxing sport of fishing, with 41% of those surveyed indicating that they had fished during the year. Suppose 180 randomly selected men are asked whether they had fished in the past year. Suppose 180 randomly selected men are asked whether they has fished in the past year.a. What is the probability that fewer than 50 had fished?
b. What is the probability that between 50 and 75 (inclusive) had fished?
c. If the 180 men selected for the interview were selected by the marketing department of a sporting-goods company based on information obtained from their mailing lists, what would you conclude about the reliability of their survey results?

Answers

Answer:

(a) The probability that fewer than 50 had fished is 0.0002.

(b) The probability that between 50 and 75 (inclusive) had fished is 0.6026.

Step-by-step explanation:

Let X = number of men who had fished during the year.

The probability of the random variable X is, p = 0.41.

A random sample of n = 180 men are selected.

The random variable X follows a Binomial distribution with parameters n = 180 and p = 0.41.

A Normal approximation to Binomial is applied when the following conditions are met,

np ≥ 10
n(1 - p) ≥ 10

Check:

$np=180*0.41=73.8>10\nn(1-p)=180* (1-0.41)=63.72>10$

Thus, the distribution of x can be approximated by a Normal distribution with:

Mean = $np=180*0.41=73.8$

Standard deviation = $√(np(1-p))=√(180*0.41*(1-0.41))=6.599$

(a)

Compute the probability that fewer than 50 had fished as follows:

$P(X<50)=P((X-\mu)/(\sigma)>(50-73.8)/(6.599))\n=P(Z<-3.61)\n=1-P(Z<3.61)\n=1-0.9998\n=0.0002$

Thus, the probability that fewer than 50 had fished is 0.0002.

(b)

Compute the probability that between 50 and 75 (inclusive) had fished as follows:

$P(50\leq X\leq 75)=P(49.5<X<75.5)\n=P((49.5-73.8)/(6.599)<(X-\mu)/(\sigma)<(75.5-73.8)/(6.599))\n=P(-3.68<Z<0.26)\n=P(Z<0.26)-P(Z<-3.68)\n=0.6026-0\n=0.6026$

Thus, the probability that between 50 and 75 (inclusive) had fished is 0.6026.

(c)

If the sample of 810 men are selected from mailing list then it is highly probable that the sample is not a representative of the true population, i.e. sports men.

Because the people interested in sports are less likely to be interested in fishing.

Thus, it could be concluded that the survey results are not reliable.

What's y in: 21y=(-205) +75+47y

Answers

The Answer Is A Fraction y= 151/47

21y=−205+75+47ySimplify: (Show steps)21y=(47y)+(−205+75)(Combine Like Terms)21y=47y+−13021y=47y−130Step 2: Subtract 47y from both sides.21y−47y=47y−130−47y−26y=−130Step 3: Divide both sides by -26.‌−26y−26‌=‌−130−26‌y=5

Simplify(5p^2-3)+ (2p^2-3p^3)

Answers

If you would like to simplify (5 * p^2 - 3) + (2 * p^2 - 3 * p^3), you can calculate this using the following steps:

(5 * p^2 - 3) + (2 * p^2 - 3 * p^3) = 5 * p^2 - 3 + 2 * p^2 - 3 * p^3 = - 3 * p^3 + 7 * p^2 - 3

The correct result would be - 3 * p^3 + 7 * p^2 - 3.

$(5 x^(2) -3)+(2 x^(2) -3 x^(3))$

In Nebraska on I-80, the speed limit is 75 mph. How long would it take you to travel 525 miles in Nebraska on I-80 if you went the speed limit the whole time?

Answers

the answer to your question is 7 hours just keep adding 75 together

Say that the economy is in an expansion, causing wages to increase by six percent. If you previously received a monthly salary of $1,375.00, what will your new monthly salary be? Round all dollar values to the nearest cent.