How do you solve the equation 0.4(2x+0.5)=3[0.2x+(-2)]-4
Answers
Answer 1
Answer:
0.4(2x+0.5)=3[0.2x+(-2)]-4
0.8x+0.2=0.6x-6-4
0.8x-0.6x=-6-4-0.2
0.2x=-10.2
x=-10.2/0.2
x=-51
0.8x+0.2=0.6x-6-4
0.8x-0.6x=-6-4-0.2
0.2x=-10.2
x=-10.2/0.2
x=-51
Answer 2
Answer:
![0.4(2x+0.5)=3[0.2x+(-2)]-4](//tex.z-dn.net/?f=0.4(2x%2B0.5)%3D3%5B0.2x%2B(-2)%5D-4)
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