MATHEMATICS HIGH SCHOOL

4y+5x=15x=8y+3

I am in Algebra 1 and kind of stuck on this problem. Can anyone help me out

Answers

Answer 1
Answer: If...x=8y+3 ⇒ 4y+5x=4y+5\cdot(8y+3)=4y+40y+15=44y+15

44y+15=15 ⇒ 44y=0 ⇒ \boxed {y=0}

x=8\cdot0+3 \boxed { x=3 }
Answer 2
Answer: 4y+5x=15x=8y+3

4y+5*(8y+3)=15

4y+40y+15=15

44y=0

y=0

x=8y+3

x=8*0+3

x=3

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If y is the principal square of root 5,what must be true

Answers

y must be a positive integer. 
Hope this was the answer you were looking for!
If it's going to be true y needs to be a positive integer
Hope that's right

Stephanie is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd} and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∩ B.{1,3,5,7,9,11}
{1,3,9}
{3,9}
{3,9,12}

Answers

The outcomes of rolling two cubes are shown in the table below (the outcomes is added up). The members of A are circled while the members of B are boxed. The members of A that also members of B is both circled and boxed.

P(A) = {3, 5, 7, 9, 11}
P(B) = {3, 6, 9, 12}
P(A∩B) = {3,9}

The intersection between the sets are the values that are common to both sets that is {3, 9}

What are sets?

Sets are arrangement of values of elements in a specified way.

Given the following sets

A = {1, 3,5, 7, 9, 11}

B = {3, 6, 9,12}

The intersection between the sets are the values that are common to both sets, hence;

A ∩ B = {3, 9}

Learn more on set here: brainly.com/question/5660357

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Find the expression in complete factored form. x^(2) + 2x-xy-2y.

Answers

Answer:   (x - y)(x + 2)

Work Shown

Factor by grouping

x^2 + 2x - xy - 2y

(x^2 + 2x) + (-xy - 2y)

x(x + 2) -y(x + 2)

(x - y)(x + 2)

The FOIL rule can be used to verify the answer is correct.

The idea of factor by grouping is to pair up the terms and factor each sub-group. Then we factor out the overall GCF, which is (x+2) in this case.

Simplify 24pn/18p^2 please and thank you

Answers

2np/27 is the simplified version of this question.

Good luck!

24pn/18p²

= 24np/18p²

= 24n/18p

= 4n/3p


I hope that's help;0

Mr. Brown is creating examples of systems of equations. He wants to have a system of equations with infinite solutions that includes the equation 5x + 2y = 8. Which equation could Mr. Brown use to complete the system so that it has infinite solutions?2x + 5y = 8
15x + 6y = 21
1.25x +0.5y = 2
6.5x + 3.5y = 9.5

Answers

In order to have a system of equations with infinite solutions, the equations must be equivalent. Two equations can be tested if they are equivalent by manipulating the equations such that they have equal coefficients for x or y.
We can take the coefficient of x as an example.

First, we reduce the coefficient of x of the given equation to 1 to make it simpler. We divide the whole equation by 5 and we get:
x + (2/5) y = 8/5

We do the same to the given options of equations.
We divide equation 1 with 2, equation 2 with 15, equation 3 with 1.25 and equation 4 with 6.5.
Compare the result with the given equation divided by 5 or x + (2/5) y = 8/5 and if it is the same, then the two equation are equivalent.

The third option: 1.25x +0.5y = 2 will give you the same equation.

Answer:

C.)1.25x +0.5y = 2

Step-by-step explanation:

For one full week, Cheng spent $12.50 per day on lunch. Determine the total amount of money he spent on lunches.

Answers

Answer:

Step-by-step explanation:

To determine the total amount of money Cheng spent on lunches for one full week, we need to multiply the amount he spent per day by the number of days in a week.

Given that Cheng spent $12.50 per day on lunch, we can calculate the total amount as follows:

$12.50 x 7 days = $87.50

Therefore, Cheng spent a total of $87.50 on lunches for one full week.

To calculate this, we multiplied the cost per day ($12.50) by the number of days in a week (7 days). This gives us the total amount of money Cheng spent on lunches.
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