According to the Central Limit Theorem, a) in a sufficiently large random sample, the distribution of a random variable X, with mean μ and standard deviation σ, is a normal distribution with mean μ and standard deviation σ/sqrt(n)b) The Central Limit Theorem does not apply to heavily skewed distributions.
True or False?
Answers
The statement is True. According to the Central Limit Theorem, in a sufficiently large random sample, the distribution of a random variable X, with mean μ and standard deviation σ, is a normal distribution with mean μ and standard deviation σ/sqrt(n).
1. The Central Limit Theorem states that the distribution of the sample means of a large sample size will approach a normal distribution, regardless of the original distribution of the population from which the sample is drawn.
2. For a sufficiently large sample size, the mean of the sample means will approach the population mean (μ) and the standard deviation of the sample means will approach the population standard deviation divided by the square root of the sample size (σ/sqrt(n)).
3. Therefore, in a sufficiently large random sample, the distribution of a random variable X, with mean μ and standard deviation σ, is a normal distribution with mean μ and standard deviation σ/sqrt(n).
This is the case because the Central Limit Theorem states that the distribution of sample means is approximately normal, regardless of the original distribution of the population from which the sample is drawn.
To know more about central limit theorem, refer here:
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The area of the base of a square notepad is 2.25 square inches. What is the length of one side of the base of the notepad?
Answers
4/3x = 1/2 Add 1/2 to both sides
x = 3/8 Multiply each side by 3/4
It is important when doing equations like these to remember that you need to multiply by the reciprocal of the fraction, not divide by it. For example, if another you have 1/2x = 1, you need to multiply by 2/1 or 2, not divide by 1/2.
B (-2,3)
C (6,-3)
A. 15 units
B. square root 250 units
C.15+ square root 125 units
D.125+ square root 125 units
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Answer:
The answer to your question is: letter C
Step-by-step explanation:
Data
A (-5 , -1)
B (-2, 3)
C (6, -3)
Perimeter = ?
Formula
distance AB
d = 5
Distance BC
d = 10
Distance AC
d = 11.2
Perimeter = 5 + 10 + 11.2
= 15 +
Answers
Answer:
see below
Step-by-step explanation:
This is a geomtric sequence
an = a1 r^(n-1)
a1 =1 and r=2
an = 2 ^(n-1)
A=a1 =1
B =a2 = 2^(2-1) =2
C =a3 = 2^(3-1) = 2^2 =4
D = a4 = 2^(4-1) = 2^3 = 8
E = a5 = 2^(5-1) = 2^4 = 16
F = a6 = 2^(6-1) = 2^5 = 32
G = a7 = 2^(7-1) = 2^6 = 64
H = a8 = 2^(8-1) = 2^7 = 128
Answers
Answer:
Kevin earns $122.5 a month.
Step-by-step explanation:
First we sum, 212.5 + 32.5 = 245 which is twice the amount of $ Kevin makes in a month, so we divide by 2, 245/2 which is 122.5
Answers
If the standard deviation is 3, we have 11-3=8 For bins:1-7 (graph of Normal distribution, or bell-shaped curve) we have 15.87% of all of the balls.
0.1587*1000=158.7.
Answer: We have approximately 159 balls in bins 1 through 7.
Answers
6. 63/100
7. 75/100 = 3/4
8. 91/100
9. 18/100 = 9/50
10. 3/100
11. 25/100 = 1/4
12. 5/100 = 1/20
13. 16/100 = 4/25
14. 1/100
15. 79/100
16. 40/100 or 4/10 = 2/5
17. 99/100
18. 30/100 or 3/10 = 3/10
19. 15/100 = 3/20
20. 84/100 = 21/25
I hope you find this answer the most helpful! :)