We let
r1 = the original radius of the cylinder
r2 = the new radius of the cylinder
h1 = the original height of the cylinder
h2 = the new height of the cylinder
SA = surface are of the cylinder
the radius and the height are shrunk down to a third of their value therefore
r2 = r1/3
h2 = h1/3
SA = 2(PI)r^2 + 2(PI)rh
SA = 2(PI)[(r1^2)/9] +2(PI)(r1/3)(h1/3)
Simplifying
SA = [2(PI)r]/9 * (r1 + h1)
240mm
Answer:
-19.8
Step-by-step explanation:
-8x^2 + 3xy - 9x - 3