If anyone knows how to do any of these PLEASE help me....im am so confused rn and our teacher sucks at explaining this stuff......
If anyone knows how to do any of these PLEASE - 2

Answers

Answer 1
Answer: take 68.2/60 = 1.137 hr
take 56.9/1.137 = 50.043 mi/hr

take 189/211 = 0.896

24.8/2 = 12.4 m
12.4/82.3 = 0.15s

Answer 2
Answer: Well, five answers for only five points is pretty slim.  But I've already got
a lot of points, and your plea for help sounds so desperate, that I think
I ought to jump in here and relieve some of your pain.

These aren't difficult problems.  The bummer is that whoever wrote them
got so interested in his dinosaur stories that he kind of hid the actual Math
and Physics under all kinds of stuff that doesn't matter.

1).     Speed  =  (distance covered) / (time to cover the distance)

                       =    (56.9 miles)  /  (68.2 minutes)

                       =      (56.9 / 68.2)  miles/minute

                       =          0.834  mile per minute.

BUT ... the question wants to know the speed in 'mph' ... miles per hour.

Well ... there are 60 minutes in an hour.  If 0.834 mile in covered in 1 minute,
then 60 times as much would be covered in 1 hour.

                    (0.834 mile/minute)  x  (60 minute/hour)  =  50.06 mile/hour

                     
            Rounded to no decimal places  =  50 mph


2).  Use the same formula:

         Speed  =  (distance covered) / (time to cover the distance)

                       =    (189 meters)  /  (211 seconds)

                       =      (189 / 211)  meters/seconds

                       =          0.8957 meters/second

     Round to 3 decimal places:      0.896  m/s


3).  The attacker jumped from 24.8 meters away.
       He already covered half of the distance.
       How far away is he now ?      1/2 of 24.8 m  =  12.4 m .
       He still has 12.4 meters left to go.

       He's moving at 82.3 meters per second.
       When will he arrive here ?

       Time  =  (distance)  /  (speed)

                  =      (12.4 meters)  /  (82.3 m/s)

                  =          (12.4 / 82.3)  seconds

                  =              0.1506 second

       Two decimal places:    0.15 second


4).    Distance  =  (speed) x (time)

                          =  ( 237 km/hr)  x (16.8 seconds) .

Do you see the problem here ?  We have the distance covered in an hour,
but we need to know how much distance is covered in only 16.8 seconds.
We really need to work out the speed in (meters per second).

OK.  237 km = 237,000 meters, so the speed is  237,000 meters/hour.

1 hour is 3,600 seconds. 
So the speed is only one 3600th of 237,000 meters in 1 second.

           (237,000 meters/hour) x (1 hour / 3600 seconds)  =  65.8333 m/s

           Distance  =  (speed)  x  (time)

                            =  (65.8333 meter/second)  x  (16.8 seconds)

                            =   (65.8333 x 16.8)  meters

                            =      1106 meters.     


5).  This is a nasty trick question.  The whole story is irrelevant,
and we don't even care how far Vinny dropped.

Anything that drops on Earth falls with the acceleration of gravity.
It doesn't matter how big or heavy or small or light it is.
Everything falls with the acceleration of gravity on Earth ...  about   9.8 m/s²  .

Related Questions

What is the speed of a swimmer if she covers 100m in 60 seconds?
Somebody plz answer these 5 only thanks!!!Will mark as brainliest:D
a car travelling at 36 km/hr due north turns west in 5 s under constant acceleration and maintains the same speed. the acceleration of the car is
Imagine you are holding an apple. Does this apple have energy?how do you know?
Which force is always directed toward the center of a circle?A. normal force B. nuclear force C. centrifugal force D. centripetal force

The precision of a voltmeter is ±0.005 V. The accepted value for a measurement is 9.016 V. Which measurement is in the accepted range?

Answers

Since there are no choices given, let us just solve for the acceptable range of values. The problem states that the precision of a voltmeter is +- 0.005 V. Meaning, the value can deviate by this amount positively or negatively. Since our accepted value is 9.016 V, then the acceptable range would be 9.011 V ~ 9.021 V.

calculate the period of a wave whose frequency is 5 Hertz and whose wavelength is one centimeter give your answer in a decimal form

Answers

The period of the wave is the reciprocal of its frequency.

       1 / (5 per second)  =  0.2 second .

The wavelength is irrelevant to the period.  But since you
gave it to us, we can also calculate the speed of the wave.

Wave speed = (frequency) x (wavelength)

                   = (5 per second) x (1cm)  =  5 cm per second

Which of the following describes what needs to occur to reduce force and to do the same amount of work?The distance that the force is exerted needs to decrease.

The mass needs to be reduced.

The distance that the force is exerted needs to increase.

The mass needs to be increased.

Answers

Answer:

The distance that the force is exerted need to increase

Explanation:

Work is defined as the product of the force and distance in the direction of applied force.

                                     W = Fd    ………………. (i)

Equation (i) shows that work done can be changed by changing either force or distance. If you reduce force, you have to increase distance accordingly to keep work done constant.

The distance that the force is exerted needs to increase

When an object is charged, what type of subatomic particle is transferred between objects?

Answers

Electrons are transferred. The object that loses some becomes positively
charged. The object that gains some becomes negatively charged.

Answer:

electrons

Explanation:

took the k12 test

Which of the following elements are non-reactive because their outer electron energy levels are full?A. Aluminum
B. Carbon
C. Krypton
D. Uranium

Answers

It would be Krypton, one of the noble gases. 

An Olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the average acceleration of the sprinter? A.
0.9 m/s

B.
110 m/s

C.
110 m/s²

D.
1.1 m/s²

Answers

Answer

Average accleration is 1.1 m/s² .

Option (D) is correct .

Explanation:

Formula

Average\ accleration = (v_(final)-v_(initial))/(t_(final)-t_(initial))

As given

An Olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds.

v_(initial) = 0\ meter\ per\ second

v_(final) = 11\ meter\ per\ second

t_(initial) = 0\ second

t_(final) = 10\ second

Putting all the values in the formula

Average\ accleration = (11-0)/(10-0)

Average\ accleration = (11)/(10)

Average accleration = 1.1 meter per second²

Therefore Average accleration is 1.1 m/s² .

Option (D) is correct .


an Olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. 1.1 m/s² is the average acceleration of the sprinter
Other Questions