Moles are the amount of substance
the break down of CCl₄ is as follows
CCl₄ --> C + 4 Cl
in the compound CCl₄ - 1 mol of CCl₄ contains 4 mol of Cl
so for every 1 mol of CCl₄ there are 4 mol of Cl
then in 8 mol of CCl₄ - there are 4 x 8 = 32 mol of Cl
so 8 mol of CCl₄ contains 32 mol of Cl
answer is 32 mol of Cl
of chlorine are present in 8 moles of .
Further Explanation:
Mole is a measure of the amount of substance. It is defined as the mass of a substance that has the same number of fundamental units as there are atoms in 12 g of carbon-12. Such fundamental units can be atoms, molecules or formula units.
In , both carbon and chlorine are non-metals. Carbon has four valence electrons whereas chlorine has seven valence electrons. Both share two electrons with each other and a single covalent bond is formed between a carbon and a chlorine atom. So carbon forms four single bonds with four chlorine atoms in order to complete its octet and the octet of chlorine is also fulfilled. This bond is formed due to sharing of the electrons and therefore is a covalent compound. (Refer to the attached image)
is a covalent compound. So 1 mole of contains 1 mole of carbon and 4 moles of Cl.
Number of moles of Cl in 1 mole of = 4
So the number of moles of Cl in 8 moles of is calculated as follows:
So 8 moles of contain 32 moles of Cl.
Learn more:
1. Identification of ionic bonding: brainly.com/question/1603987
2. Which is a covalent compound? brainly.com/question/2083444
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Ionic and covalent compounds
Keywords: covalent compounds. chlorine, carbon, mole, non-metal, mutual sharing, molecular bond, hydrogen, chlorine, CCl4, brittle, enthalpy of fusion, heat, electricity, conductors, boiling points, positively charged, negatively charged.
B) Drug
C) Medicine
D) Screening Tool
Ohp xD nvm, the answer is A !
During the test trial, the sugar pill given to the control group is called a placebo. Therefore, the correct option is A. Placebo
A placebo is any drug or a treatment with no active substances, for example a sugar pill.
During clinical trials, usually one group takes the actual drug while the other group takes the placebo without being aware of it.
Placebo is an inactive treatment given to a group of people that is made to look like the real drug, but in reality it simply makes the patient believe they're being treated with the drug and that the drug will help them relieve from the symptoms.
By comparing the results from the two groups, this method helps in analyzing the accurate effects of the drug on the patients and helps in proving that it was the drug that actually treated the symptom and that the treatment did not occur by chance or just a mere belief of the patient thinking they will get better because they're being treated.
This approach helps reduce bias and ensures that the trial's results are more accurate and reliable.
So, the sugar pill given to the control group is called a placebo. Therefore, the correct option is A. Placebo
To learn more about placebo, click on
#SPJ2
C- it emitted an alpha particle in a nuclear reaction (just took the edg test)
b. -115.6 kcal
c. -173.4 kcal
d. -231.2 kcal
e. -462.4 kcal
35
65
95
Answer : The correct option is, 30 protons
Explanation :
Element = Zinc
Atomic number = 30
Atomic mass number = 65
As we know that the atomic number is equal to the number of electrons and number of protons.
Atomic number = Number of electrons = Number of protons = 30
Number of neutrons = Atomic mass - Number of protons = 65 - 30 = 35
Therefore, the number of protons an uncharged zinc atom have 30 protons.
Answer:
30 protons
Explanation:
i took the test
Given that the molar mass of CO2 is 44.01 g/mol, how many liters of oxygen is required at STP to produce 88.0 g of CO2 from this reaction?
44.8 L
45.00 L
89.55 L
89.6 L
89.6 L of O₂
The balanced chemical equation is as,
CH₄ + 2 O₂ → CO₂ + 2 H₂O
As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,
44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂
So,
88 g CO₂ will be produced by = X L of O₂
Solving for X,
X = (88 g × 44.8 L) ÷ 44 g
X = 89.6 L of O₂
Cl2(aq) + 2Brmc003-1.jpg(aq) mc003-2.jpg 2Clmc003-3.jpg(aq) + Br2(aq)
I think the chemical reaction is:
Cl2(aq) + 2Br-(aq) = 2Cl-(aq) + Br2(aq)
The oxidation in this reaction is the reaction for bromine where the charge goes from -1 to a neutral charge while the reduction reaction is showed by the chlorine from a neutral charge to a -1 charge.