The controlled fusion reaction is a nuclear reaction in which two or more atomic nuclei come very close and then collide at a very high speed and join to form a nucleus. The mass of the new nucleus is slightly less than the sum of its components b an amount known as binding energy.
B) unequal heating of different parts of earth
C) differences in elevation on different landmasses
D) greenhouse gases
(no guessing please )
(2) HCl (4) HI
The balanced equation of the reaction between hydrogen and nitrogen to produce ammonia would be:
Ammonia is produced when nitrogen reacts with hydrogen.
Stoichiometrically, 1 mole of nitrogen is required to react with 3 moles of hydrogen with 2 moles of ammonia being the product.
Thus, the balanced chemical equation for the reaction would become:
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Answer:
Balanced chemical equation:
N₂ + 3H₂ → 2NH₃
Explanation:
Chemical equation:
N₂ + H₂ → NH₃
Balanced chemical equation:
N₂ + 3H₂ → 2NH₃
Step1:
Left side of equation Right side of equation
N = 2 N = 1
H = 2 H = 3
Step 2:
N₂ + H₂ → 2NH₃
Left side of equation Right side of equation
N = 2 N = 2
H = 2 H = 6
Step 3:
N₂ + 3H₂ → 2NH₃
Left side of equation Right side of equation
N = 2 N = 2
H = 6 H = 6
ionic compounds lose or gain electrons to become stable.
ionic compounds are bonds between metals and nonmetals.
molecular or covalent compounds share one or more electrons to become stable.
molecular or covalent compounds are bonds between nonmetals.
An example of an ionic compound is sodium chloride (NaCl). An example of a molecular compound is carbon dioxide (CO2).
One example of an ionic compound is sodium chloride (NaCl), where sodium (Na) is a metal that forms a positively charged ion and chlorine (Cl) is a nonmetal that forms a negatively charged ion. The formula for a molecular compound is represented by carbon dioxide (CO2), where carbon (C) and oxygen (O) atoms share electrons to form covalent bonds.
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72.7% is the percent by mass of oxygen in carbon dioxide. A percent is obtained by multiplying the result by 100.
One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.
Molar mass of oxygen = 32 g/mole
Molar mass of carbon dioxide = 44 g/mole
mass percentage of oxygen =(molar mass of oxygen/molar mass of carbon dioxide)× 100
=(32/44)× 100
=72.7%
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Answer : The percent by mass of oxygen in carbon dioxide is, 72.72%
Solution : Given,
Molar mass of oxygen = 16 g/mole
Molar mass of carbon dioxide = 44 g/mole
As we know that there are 2 atoms of oxygen and 1 atom of carbon present in the carbon dioxide.
So, the molar mass of oxygen, = 2 × 16 = 32 g/mole
Now we have to calculate the percent by mass of oxygen in carbon dioxide.
Now put all the given values in this expression, we get
Therefore, the percent by mass of oxygen in carbon dioxide is, 72.72%