Answer:
350
Step-by-step explanation:
Using the normal distribution, it is found that:
a) There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive.
b) There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate chips.
c) 0.3446 = 34.46% of bags contains more than 1200 chocolate chips.
d) The bag is in the 91st percentile.
In a normal distribution with mean and standard deviation, the z-score of a measure X is given by:
In this problem:
Item a:
The probability is the p-value of Z when X = 1500 subtracted by the p-value of Z when X = 1000, thus:
X = 1500:
has a p-value of 0.9726.
X = 1000:
has a p-value of 0.0256.
Then, 0.9726 - 0.0256 = 0.947
There is a 0.947 = 94.7% probability that a randomly selected bag contains between 1000 and 1500 chocolate chips, inclusive.
Item b:
This probability is the p-value of Z when X = 1025, thus:
has a p-value of 0.0392.
There is a 0.0392 = 3.92% probability that a randomly selected bag contains fewer than 1025 chocolate chips.
Item c:
This proportion is 1 subtracted by the p-value of Z when X = 1200, thus:
has a p-value of 0.3446.
0.3446 = 34.46% of bags contains more than 1200 chocolate chips.
Item d:
This percentile is the p-value of Z when X = 1425, thus:
has a p-value of 0.91.
The bag is in the 91st percentile.
A similar problem is given at brainly.com/question/13680644
The probability and percentiles can be found using the z-score formula and then looking these z-scores up in the standard normal distribution table.
In this question, we're dealing with a normal distribution. For a normal distribution, probabilities can be calculated using the z-score formula which is given by Z = (X - μ) / σ, where X is the value from which you want to find the probability, μ is the mean and σ is the standard deviation.
(a) To find the probability that a randomly selected bag has between 1000 and 1500 chocolate chips, we need to find the z-scores for both 1000 and 1500 and then find the area between these two z-scores in the standard normal distribution table. (b) To find the probability that a randomly selected bag has less than 1025 chips, we find the z-score for 1025 and find the area to the left of it in the standard normal distribution table. (c) To find the proportion of bags containing more than 1200 chips, we find the z-score for 1200 and then find the area to the right of it in the standard normal distribution table. (d) Percentile rank can be found by finding the z-score for 1425 chips, and then finding the corresponding percentile in the standard normal distribution table.
#SPJ3
Answer:
Step-by-step explanation:
Assuming this info from R
hist(gifted$count)
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 21.00 28.00 31.00 30.69 34.25 39.00
## Sd
## [1] 4.314887
Data given and notation
represent the mean
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a two sided test the p value would be:
Answer:
true. zero is an integer number
Step-by-step explanation:
Answer:
True, it is Known as a neutral integer Because it is neither negative or positive whole number
Step-by-step explanation:
B.68,340 ft.
C.250 ft.
D.131 ft.
Answer:
131ft is the amount of fencing material needed
Step-by-step explanation:
Perimeter is the distance around a shape: we have to sum all the distances
P = d1 + d2 + d3
P = 34 ft + 30 ft + 67 ft = 131 ft
Answer:
D. 131 ft.
Step-by-step explanation:
If Sarah is planning to fence in her backyard garden and one side of the garden is 34 feet long, another side is 30 feet long, and the third side is 67 feet long. The perimeter of Sarah’s garden to determine the amount of fencing material needed is 131 feet.
Answer:
So simple
4 pages = 6 min
1 page = 6/4 min
6 pages = 6 × 6/4
6 pages = 9 min