The molecules AlCl3, CCl4, SCl2, and S3 have different geometries and bond angles due to the number of electron bonding pairs. As such, by increasing bond angles, the order is SCl2 < CCl4 < AlCl3 < S3.
The question asks us to sort the molecules AlCl3, CCl4, SCl2, and S3 by increasing bond angles about the central atom. To do this, we need to examine the geometry and the bond angles produced by the electronic arrangements of each molecule.
In AlCl3, the central atom, Al, has three bonded pairs of electrons resulting in a trigonal planar structure with bond angles of 120°. In CCl4, carbon is the central atom, and it forms four bonds with chlorine atoms, creating a tetrahedral structure. The bond angle for this molecule is approximately 109.5°. For SCl2, sulfur forms two bonds and has two lone pairs of electrons. The VSEPR model predicts a bent or V shape for the molecule, resulting in bond angles less than 109.5°. Lastly, S3 is a non-polar molecule with bond angles of 120°.
Therefore, the correct order of increasing bond angles would be SCl2 < CCl4 < AlCl3 < S3.
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1 mol of Lead weighs more than 1 mol of Gold because lead has a higher atomic mass (207.2 g/mol) compared to gold's atomic mass (197.0 g/mol). Option D. is correct.
Consider the atomic masses of both gold and lead, as the question involves comparing a mole of each. Importantly, the molar mass of any substance is numerically equivalent to its atomic weight in Atomic Mass Units (amu). The atomic mass of gold is approximately 197.0 amu while lead has an atomic mass of around 207.2 amu.
Therefore, a 1 mol of Lead (207.2 g) would weigh more than 1 mol of Gold (197.0 g).
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Answer:Hello,
Neon is a noble gas. It is located Group 18 and the oxidation number is 10.
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