THE EXPRESSION (TAN THETA) (CSC THETA) IS EQUAL TO?

Answers

Answer 1

Answer: $tan\theta\cdot csc\theta=(sin\theta)/(cos\theta)\cdot(1)/(sin\theta)=(1)/(cos\theta)=sec\theta$

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WHICH EXPRESSION IS EQUIVALENT TO (3X5+8X3)-(7X2-6X3)

Solve for x
logx+log(x-4)=2log5

Answers

$\log{x} + \log{(x-4)} = 2 \log{5}\n\n\log{\big(x(x-4)\big)} = \log{5^2}\n\n\log{(x^2-4x)} = \log{25} \n\nx^2-4x = 25\n\nx^2-4x-25=0 \n\nx = (4 \pm√(16+100))/(2) \n\nx = (4\pm2√(29))/(2) \n\nx = 2 \pm √(29) \n\n\text{But } x > 0 \implies x = 2 + √(29)$

$D:x>0\wedge x>4\nD:x>4\n\n\log x+\log(x-4)=2\log5\n\log x(x-4)=\log25\nx(x-4)=25\nx^2-4x-25=0\nx^2-4x+4-29=0\n(x-2)^2=29\nx-2=√(29) \vee x-2=-√(29)\nx=2+√(29) \vee x=2-√(29)\n2-√(29)\not>4\n\Downarrow\n\boxed{x=2+√(49)}$

Which is the graph of linear inequality 2y > x – 2?

Answers

The graph of linear inequality (2y > x – 2) can be drawn by determining the x-intercept and y-intercept of the equation (2y = x - 2).

Given :

Inequality -- 2y > x – 2

The graph of the inequality can be drawn by using the following steps:

Step 1 - First find the y-intercept by putting (x = 0) in equatiuon (2y = x – 2).

$2y = -2$

y = -1

Step 2 - Now, find x-intercept by putting (y = 0) in equatiuon (2y = x – 2).

$0=x-2$

x = 2

Step 3 - Now, draw the line that passes through (0,-1) and (2,0).

Step 4 - Now, shade the upper part of the line, the resulting graph is the graph of (2y > x – 2).

Therefore, the correct option is C).

For more information, refer to the link given below:

brainly.com/question/4700926

The answer is 3C. Rate 5 stars

Factor the following equation to solve for "x"; x^{2} - 8x - 20 = 0

Answers

x² - 8x - 20 = 0

Factor the left side:

(x + 2) (x - 10) = 0

That's a true statement if (x = -2) or if (x= 10), so those are your solutions.

x = -2
x = 10

By the way ... you don't factor an equation. You can only factor an expression.

For today’s lunch, a school cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn. 1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch. If a can of beans cost $2.00 and a can of corn cost $3.00, what is the maximum amount of money required to feed all of the students either beans or corn?A: $180

B: $195

C: $210

D: $225

Answers

Answer:

Option B.

Step-by-step explanation:

Let x be the number of cans of beans and y be the number of cans of corn.

Cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn.

$x\leq 60$

$y\leq 45$

1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch.

$5x+6y\leq 420$

Can of beans cost $2.00 and a can of corn cost $3.00.

Objective function, Z=2x+3y

The required linear programming problem is

Objective function, Z=2x+3y

Subject to the constraints

$x\leq 60$

$y\leq 45$

$5x+6y\leq 420$

$x\geq 0, y\geq 0$ (Only 1st quadrant)

Draw the graph of these constraints as shown below.

The verities of common shaded region are (0,45), (30,45), (60,20), (60,0), (0,0).

Points Z=2x+3y

(0,0) 0

(0,45) 135

(30,45) 195

(60,20) 180

(60,0) 120

The maximum amount of money required to feed all of the students either beans or corn is $195.

Number of cans of beans = 30

Number of cans of corn = 45

Therefore, the correct option is B.

I would go with B, one hundred ninety five dollars. Hope that this would help you..

One-fifth of a swarm of bees is resting on a kadaba bush and a third on a silindha bush; three timesthe difference between these two numbers is on a kutaja, and a single bee has flown off in the breeze drawn by the odor of a jasmine and a pandam. Tell me, beautiful maiden, how many bees are there?