The image produced by a concave lens is always virtual. Is this true or false?

Answers

Answer 1

Answer: $Concave\text{ lens always }produce\text{ }virtual\text{ image},\text{ hence the statement is true}$

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Problem 1: You go outside on a hot, sunny summer day and you feel the warm sun on your skin. What causes this warmth?A. The sun heats the air directly around your skin.

B. Waves of light carry energy directly to your skin.

C. Light causes surface waves on your skin.

D. Water vapor in the air warms your skin.

PRoblem 2: When a water wave runs into you at the beach, what causes you to get knocked down?

A. air molecules in front of the wave

B. the wave's energy

C. periodic motion

D. friction

Answers

1) B
The sun transfers energy to the earth via radiation. This radiation is a form of electromagnetic radiation so it heats your skin direclty
2) B
The waves' energy is transferred to you and you lose your footing and fall

B.waves of light carry energy directly to your skin.

What type of force cause an object to accelerate??

Answers

ANY force causes an object to accelerate, just as long as there are not
some other forces on the object that cancel out the first one.

Are you looking for the answer ... an "UNBALANCED" force ?
That's a very poor way to describe it, because there's no such thing
as a balanced or unbalanced force. The thing that's balanced or
unbalanced is a GROUP of forces, not a single force.

A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.0 10-4 J. (a) Find the magnitude and direction of the electric force that acts on the particle. _______N the direction of motion (along, against, perpendicular)
(b) Find the magnitude and direction of the electric field that the particle experiences. _______N/C the direction of motion (along, against, perpendicular)

Answers

The magnitude of the electric field is 4000 N/C while the direction of the electric field is along the direction of the motion of the charge.

Given to us

Charge of the particle, q = +1.5 µC = 1.5 x 10⁻⁶

Distance between points A and B, d = 0.15 m

The particle's electric potential energy at A and B

= $\rm EPE_A - EPE_B$ = +9.0x10⁻⁴ J

What is the magnitude and direction of the electric force that acts on the particle?

The electric charge in electric potential energy is equal to the work done by an electric field. therefore,

$\rm W=EPE_A - EPE_B$

W = 9.0x10⁻⁴ J

We know that work done by the system can be given as,

$\rm Work = force* displacement$

Substitute the values,

$9 * 10^(-4)= F * 0.15$

F = 1.5 x 10⁻³ N

Thus, the magnitude of the force is 1.5 x 10⁻³ N while its direction is along with the motion of the charge.

What is the magnitude and direction of the electric field that the particle experiences?

We know the relationship between electrostatic and electric force, therefore,

$\rm Force = charge* Electric\ field$

Substitute the values,

$6* 10^(-3)=1.5* 10^(-6) * \rm E$

E = 4000 N/C

Hence, the magnitude of the electric field is 4000 N/C while the direction of the electric field is along the direction of the motion of the charge.

Learn more about the Electric field:

brainly.com/question/12757739

Answer:

Part a)

$F = 6 * 10^(-3) N$

Direction of force is along the motion of charge

Part b)

$E = 4000 N/C$

direction of electric field is along the direction of motion

Explanation:

Part a)

As we know that the change in electric potential energy is equal to the work done by electric field

$W = EPE_A - EPE_B$

$W = 9.0 * 10^(-4) J$

now from the equation of work done we know that

$W = F.d$

$(9.0 * 10^(-4)) = F(0.15)$

$F = 6 * 10^(-3) N$

Direction of force is along the motion of charge

Part b)

As we know the relation between electrostatic force and electric field given as

$F = qE$

$(6 * 10^(-3)) = 1.5 * 10^(-6) E$

$E = 4000 N/C$

direction of electric field is along the direction of motion

An electron in a hydrogen atom undergoes a transition from the n = 3 level to the n = 6 level. To accomplish this, energy, in the form of light, must be absorbed by the hydrogen atom. Calculate the energy of the light (in kJ/photon) associated with this transition.

Answers

Answer: $1.816* 10^(-19) J$

Explanation:

Given

$E=(hc)/(\lambda )$

$E=2.18* 10^(-18)((1)/(n_1^2)-(1)/(n_2^2))$

where h=Planck constant

c=speed of light

$E=2.18* 10^(-18)((1)/(3^2)-(1)/(6^2))$

$E=2.18* 10^(-18)* (1)/(12)$

$E=1.816* 10^(-19) J$

Answer:

1.82 × 10⁻¹⁹ J

Explanation:

The Bohr model of the atom states that the energy required to transition between two energy levels is equal to the difference between the inverse squares of the energy levels multiplied by the Rydberg constant:

In terms of density and humidity, which conditions characterize a high-pressure area? A.high density, high humidity

B.high density, low humidity

C.low density, low humidity

D.low density, high humidity

Answers

Answer
A
Source: Meteorologist/Storms spotter & chaser

Answer:

A (high density and high humidity)

Explanation: Hope this helps :)

1. On which date does the Antarctic Circle have 24 hours of daylight? A. June 21B. March 21
C. September 21
D. December 21

2. When energy is transferred to air, what happens to the particles of air? A. They move slower.
B. They move faster.
C. They cool down.
D. none of the above

Answers

The date in which the Antarctic Circle has 24 hours of daylight on December 21st every year. When energy is transferred to air the particles of air become more excited and move around faster.

1. On which date does the Antarctic Circle have 24 hours of daylight?

the answer is D

2. when energy is transferred to air, what happens to the particles of Air?

the answer is B

HOPE THIS HELPED

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