This question involves the concept of magnification.
The distance to the magnified image will be "24 cm".
The magnification of the magnifying glass is given by the following formula:
where,
Therefore,
q = (4)(6 cm)
q = 24 cm
Learn more about magnification here:
Answer:
Both vectors have the same X and Y components therefore
the angle between the two vectors is zero
(B) is correct
X-ray scanners
Answer:
Explanation:
If a small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground and reaches a terminal speed after falling 0.400m, the Change in distance will be 1.90m - 0.400 = 1.50m
If it takes 5.4secs fo r the Styrofoam to reach the ground, the terminal velocity will be expressed as;
Vt = change in distance/time
Vt = 1.5m/5.4s
Vt = 0.28m/s
Note that the Styrofoam reaches its final velocity when the acceleration is zero.
To get the constant value B from the equation a = g-Bv
a = 0m/s²
g = 9.81m/s²
v = 0.28m/s
Substituting the parameters into the formula.
0 = 9.81-0.28B
-9.81 = -0.28B
Divide both sides by -0.28
B = -9.81/-0.28
B = 35.04
b) at t = 0sec, the initial terminal velocity is also zero.
Substituting v = 0 into the equation to get the acceleration.
a = g-Bv
a = g-B(0)
a = g
Hence the acceleration at t =0s is equal to the acceleration due to gravity which is 9.81m/s²
c) Given speed v = 0.150m/s
g = 9.81m/s²
B = 35.04
Substituting the given data into the equation a = g-Bv
a = 9.81-35.04(0.15)
a = 9.81 - 5.26
a = 4.55m/s²
Answer:
a
b
c
Explanation:
From the question we are told that
The fall height is
The magnitude of the acceleration is
The height at which terminal speed is attained is
The time taken to reach the ground from the terminal velocity height is t = 5.40 s
Generally the height which object traveled with terminal velocity is
=>
=>
Generally the terminal velocity is mathematically represented as
=>
=>
Generally at terminal velocity , acceleration is zero so
substituting
=>
=>
Generally at t = 0 s the velocity v = 0 (That no motion at time zero)
So from acceleration equation
=>
Generally when the speed v = 0.150 m/s
The acceleration is
=>
Answer:
To check the movement of the snail.
Explanation:
the answer was right :)
The things that a scientist should consider while observing the force is the environmental conditions,the force that is expected to act on the dam, the means to contain that force, and compare different types of designs in accordance with the location of the dam