4(X-1)-3(X^2+2X+3)-7(X+7)

Answers

Answer 1

Answer: $4(x-1)-3(x^2+2x+3)-7(x+7) =\n 4x-4-3x^2-6x-9-7x-49=\n -3x^2-9x-62$

- 65

Hope this helps you

You earn $420 per week. You pay social security taxes of 7.65%, federal taxes of 22%, and state taxes of 5.95%. What is your take home pay?

Answers

If you would like to know what is your take home pay, you can calculate this using the following steps:

social security taxes: $420 - 7.65% * $420 = 420 - 7.65/100 * 420 = $387.87
federal taxes: $387.87 - 22% * $387.87 = 387.87 - 22/100 * 387.87 = $302.54
state taxes: $302.54 - 5.95% * $302.54 = 302.54 - 5.95/100 * 302.54 = $284.54

Your take home pay would be $284.54.

A store manager earns $ 24.00 per hour. If the manager works 8 hours one day and donates 1 10 of the day's earnings to charity, how much of the earnings are left?

Answers

If u meant $1.10 donated then it would be $190.9

But if u donated 110 then it would be $82

Joey is buying plants for his garden. He wants to have at least twice as many flowering plants as nonflowering plants and a minimum of 36 plants in his garden. Flowering plants sell for $8, and nonflowering plants sell for $5. Joey wants to purchase a combination of plants that minimizes cost. Let x represent the number of flowering plants and y represent the number of nonflowering plants. What are the vertices of the feasible region for this problem?
(0, 0), (0, 36), (24, 12)
(0, 36), (24, 12)
(0, 36), (24, 12), (36, 0)
(24, 12), (36, 0)

Answers

(24, 12) and (36, 0). The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0. These two points satisfy both conditions and both sum to 36.

Answer: (24, 12), (36, 0)

Step-by-step explanation:

Let x be the number of flowering plants and y be the number of non- flowering plants.

According to the question, we need to minimize the cost of plants.

$Minimize:8x+5y$

Subject to the constraints,

$2y\leq\ x\nx+y\geq36$

To find the feasible region find the points of the equation to plot it on graph.

For the first equation $2y=x$ , at x=0 y=0 and at x=4, y=2

For the second equation $x+y=36$ , at x=0 y=36 and at x=36, y=0

Thus points for eq (1) are (0,0) and (4,2) and points for equation (2) are (0,36) and (36,0).

Now, plot it on graph, we get the shaded feasible region as shown in the graph.

and we can see the vertices of the feasible region = (24, 12), (36, 0)

A car rents for $45.00 per day plus 21 cents per mile. You are on a daily budget of $66.00 per day. What mileage will allow you to stay within your budget?

Answers

45+.21m is less than or equal to 66
-45 from both sides

.21m is less than or equal to 21
/.21 from both sides

m is less than or equal to 1000

you can go no more than 1,000 miles.

What is the approximate area of the shaded sector in the circle shown below? A) 26.5 cm^2 B) 11.78 cm^2 C) 5.89 cm^2 D) 53.0 cm^2