MATHEMATICS COLLEGE

Hello I am needing help on this word problem please. I think it's 30 but I'm questioning myself

Answers

Answer 1

Answer:

Solution:

Since 5 pounds of meat will feed about 26 people.

Thus;

$\begin{gathered} (5)/(26)lb\text{ would feed 1 person} \n \n =0.1923 \end{gathered}$

If she is expecting 156 people, she should prepare;

$\begin{gathered} (0.1923*156)lb\text{ of meat} \n \n \approx30lb \end{gathered}$

ANSWER: 30lb

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Will wanted to track the growth of various fruits in his garden, so he decided to label them. His garden had APPLES labeled 1,2,3,4,5,6, LEMONS labeled 1,2, and MELONS labeled 1,2,3. If a single fruit is picked at random, what is the probability that the fruit is an APPLE or has an EVEN number?

Answers

Using the probability concept, it is found that there is a 0.7273 = 72.73% probability that the fruit is an APPLE or has an EVEN number.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

There are 11 options, hence $T = 11$ .
Of those, there are 6 options which land on Apple, plus 2 options which does not land on apple but have an even number, hence $D = 6 + 2 = 8$

Then, the probability is:

$p = (D)/(T) = (8)/(11) = 0.7273$

0.7273 = 72.73% probability that the fruit is an APPLE or has an EVEN number.

A similar problem involving the probability concept is given at brainly.com/question/15536019

Answer:

8 in 11 or 0.7272

Step-by-step explanation:

Between 6 apples. 2 lemons and 3 melons, Will has a total of 11 fruits in his garden. There are three apples labeled with even numbers (2,4 and 6), one melon (2) and one lemon (2), for a total of five fruits.

The probability that a randomly selected fruit is an APPLE or has an EVEN number is given by the probability that it is an apple, P(A), added to the probability that it is even, P(E), minus the probability that it is an even apple, P(A and E):

$P(A\ or\ E) = P(A) +P(E) - P(A\ and\ E)\nP(A\ or\ E) = (6)/(11)+(5)/(11)-(3)/(11) \nP(A\ or\ E) = 0.7272$

There is a 8 in 11, or a 0.7272 chance that the fruit is an APPLE or has an EVEN number.

Wil someone help me convert all of these to metric, for those that can be.3 tablespoons vegetable oil
1 1/2 pounds skinless boneless chicken breast
Salt and pepper
2 teaspoons cumin powder
2 teaspoons garlic powder
1 teaspoon Mexican Spice Blend
1 red onion, chopped
2 cloves garlic, minced
1 cup frozen corn, thawed
5 canned whole green chiles, seeded and coarsely chopped
4 canned chipotle chiles, seeded and minced
1 (28-ounce) can stewed tomatoes
1/2 teaspoon all-purpose flour
16 corn tortillas
1 1/2 cups enchilada sauce, canned 1 cup shredded Cheddar and Jack cheeses

Answers

Approximate conversions for cooking are ...

1 tsp ≈ 5 mL, so 1/2 tsp is about 2.5 mL

1 Tbsp ≈ 15 mL

1 cup ≈ 240 mL, so 1 1/2 cups ≈ 355 mL*

1 1/2 lb ≈ 680 g

_____

* 1 cup is about 236.6 mL.

_____

Many cookbooks have tables of equivalents.

Part A Each time you press F9 on your keyboard, you see an alternate life for Jacob, with his status for each age range shown as either alive or dead. If the dead were first to appear for the age range of 75 to 76, for example, this would mean that Jacob died between the ages of 75 and 76, or that he lived to be 75 years old. Press F9 on your keyboard five times and see how long Jacob lives in each of his alternate lives. How long did Jacob live each time? Part B The rest of the potential clients are similar to Jacob, but since they’ve already lived parts of their lives, their status will always be alive for the age ranges that they’ve already lived. For example, Carol is 44 years old, so no matter how many times you press F9 on your keyboard, Carol’s status will always be alive for all the age ranges up to 43–44. Starting with the age range of 44–45, however, there is the possibility that Carol’s status will be dead. Press F9 on your keyboard five more times and see how long Carol lives in each of her alternate lives. Remember that she will always live to be at least 44 years old, since she is already 44 years old. How long did Carol live each time? Part C Now you will find the percent survival of each of your eight clients to the end of his or her policy using the simulation in the spreadsheet. For each potential client, you will see whether he or she would be alive at the end of his or her policy. The cells in the spreadsheet that you should look at to determine this are highlighted in yellow. Next, go to the worksheet labeled Task 2b and record either alive or dead for the first trial. Once you do this, the All column will say yes if all the clients were alive at the end of their policies or no if all the clients were not alive at the end of their policies. Were all the clients alive at the end of their policies in the first trial? Part D Next, go back to the Task 2a worksheet, press F9, and repeat this process until you have recorded 20 trials in the Task 2b worksheet. In the Percent Survived row at the bottom of the table on the Task 2b worksheet, it will show the percentage of times each client survived to the end of his or her policy, and it will also show the percentage of times that all of the clients survived to the end of their respective policies. Check to see whether these percentages are in line with the probabilities that you calculated in questions 1 through 9 in Task 1. Now save your spreadsheet and submit it to your teacher using the drop box. Are your probabilities from the simulation close to the probabilities you originally calculated?

Answers

Answer:

Jacob:

Alive 69-70

alive 79-80

alive 62-63

alive 73-74

alive 78-Died 79

Carol:

alive 88-89

alive 67-68

alive 99-100

alive 73-74

alive 94- Died 95

Step-by-step explanation:

Set up and evaluate the optimization problems. (Enter your answers as comma-separated lists.) Find two positive integers such that their sum is 14, and the sum of their squares is minimized. Find two positive integers such that their sum is 14, and the sum of their squares is maximized.

Answers

Answer and Step-by-step explanation:

Let x and y be two positive integers and their sum is 14:

X + y = 14

And the sum of square of this number is:

f = x2 + y2

= x2+ (14 – x)2

Differentiate with respect to x, we get:

F’(x) = [ x2 + (14 – x)2]’ = 0

2x + 2(14-x)(-1) = 0

2x +( 28 – 2x)(-1) = 0

2x – 28 +2x = 0

2x + 2x = 28

4x = 28

X = 7

Hence, y = 14 – x = 14 -7 = 7

Now taking second derivative test:

F”(x) > 0

For x = y = 7,f reaches its maximum value:

(7)2 + (7)2 = 49 + 49

= 98

F at endpoints x Є [ 0, 14]

F(0) = 02 + (14 – 0)2

= 196

F(14) = (14)2 + (14 – 14)2

= 196

Hence the sum of squares of these numbers is minimum when x = y = 7

And maximum when numbers are 0 and 14.

Final answer:

To find two positive integers such that their sum is 14, and the sum of their squares is minimized, we need to consider all possible pairs of positive integers and calculate their sums of squares. The pair (6, 8) has the minimum sum of squares of 100. To find two positive integers such that their sum is 14, and the sum of their squares is maximized, the pairs (1, 13) and (2, 12) both have the maximum sum of squares of 170. Since we need to find two positive integers, the pair (1, 13) is the answer.

Explanation:

To find two positive integers such that their sum is 14 and the sum of their squares is minimized, we need to consider all possible pairs of positive integers that add up to 14 and calculate their sums of squares. Let's list all the pairs:

1 and 13: 1^2 + 13^2 = 170
2 and 12: 2^2 + 12^2 = 148
3 and 11: 3^2 + 11^2 = 130
4 and 10: 4^2 + 10^2 = 116
5 and 9: 5^2 + 9^2 = 106
6 and 8: 6^2 + 8^2 = 100
7 and 7: 7^2 + 7^2 = 98

From the list, we can see that the pair (6, 8) has the minimum sum of squares, which is 100.

Similarly, to find two positive integers such that their sum is 14 and the sum of their squares is maximized, we need to again consider all possible pairs and calculate their sums of squares. Let's list the pairs:

1 and 13: 1^2 + 13^2 = 170
2 and 12: 2^2 + 12^2 = 148
3 and 11: 3^2 + 11^2 = 130
4 and 10: 4^2 + 10^2 = 116
5 and 9: 5^2 + 9^2 = 106
6 and 8: 6^2 + 8^2 = 100
7 and 7: 7^2 + 7^2 = 98

From the list, we can see that the pair (1, 13) and the pair (2, 12) both have the maximum sum of squares, which is 170. Since we need to find two positive integers, the pair (1, 13) is the answer.