Where does f(x)=3x2-11x-4 intersect the x axis?The negative x-intercept is at (___,0)
The positive x-intercept is at (___,0)

we know that  

The x-intercept is the value of x when the value of the function is equal to zero.

in this problem  we have

To find the x-intercepts equate the function to zero

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares

square root both sides

therefore

the answer is

The negative x-intercept is at

The positive x-intercept is at

The negative x-intercept is (-1/3, 0) and the positive x-intercept is (4,0)

Intercepts

Given the expression 3x²-11x-4, the x intercept occur that the point where f(x) = 0.

The function will become 3x²-11x-4 = 0

factorising expressions

Factorize the result to have:

• 3x² -12x + x - 4 = 0

Group the function to have;

• (3x²-12x)+(x-4) = 0

Factor out the GCF

3x(x-4) + 1(x-4) = 0

(3x+1) (x-4) = 0

Get the x-intercepts

3x+1 = 0

x = -1/3

Hence the negative x-intercept is (-1/3, 0)

Also, x-4 = 0

x = 4

Hence the positive x-intercept is (4, 0)

Learn more on intercepts here: brainly.com/question/24212383