MATHEMATICS MIDDLE SCHOOL

What is the first step needed to solve 2 over 5 multiplied by x minus 6 equals negative 16?A.) Subtract 16 from both sides
B.)Add 6 to both sides
C.) Divide both sides by 5
D.) Multiply both sides by 2

Answers

Answer 1
Answer:

9514 1404 393

Answer:

  B.)  Add 6 to both sides

Step-by-step explanation:

Actually, the first step is to look at the given equation and at what is being asked. The next step is to formulate a strategy for finding what is asked.

Here, the equation is ...

  (2)/(5)x-6=-16

As part of our assessment of this, we notice that ...

  • x is multiplied by 2/5
  • 6 is subtracted

We are asked for the first step to solve this equation. The usual strategy for solving such an equation is to undo the steps done to the variable, in reverse order. In the above assessment, we notice the last step is subtracting 6 from the product. So, our first step in finding the value of x is to undo that subtraction:

  add 6 to both sides

__

Additional comment

We also notice as part of our assessment that the equation contains the fraction 2/5, which has a denominator of 5. If we choose to eliminate fractions as a first step in our solution strategy, we would multiply both sides by 5. Notice that this is not one of the offered choices.
Answer 2
Answer:

Answer:

A) Add One-sixth to both sides.

Step-by-step explanation:

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W/5-10= -4 equals to?

Answers

w/-5-10=-4

Simplify both sides of the equation

w/5-10=-4

1/5 w +-10=-4

1/5 w-10=-4

Add 10 to both sides

1/5 w -10 +10= -4=10

1/5 w =6

Multiply both sides by 5

5(1/5 w )=(5)*(6)

w=30

Check my answer

Replace w by 30

30/5-10=-4

-4=-4


I hope that's help and have a great night .

How to divide 5.6÷16 Check your work with multiplication

Answers

5.6/16 = 56/160 (multiplied both numerator and denominator by 10). Simplify to 7/20, you get 0.35

Evaluate each expression (25^-3/2)^1/3

Answers

Following are the calculation to the given expression:

Given:

\to (25^{-(3)/(2))^{(1)/(3)}

To find:

evaluate expression=?

Solution:

\to (25^{-(3)/(2))^{(1)/(3)}= ((5^2)^{-(3)/(2))^{(1)/(3)}\n

                = (5^{2 * -(3)/(2)})^{(1)/(3)}\n\n= (5^(-3))^{(1)/(3)}\n \n= 5^{{-3}* (1)/(3)}\n \n= 5^(-1)\n\n=(1)/(5)

The final answer is "{(1)/(5)}".

Learn more:

brainly.com/question/8061466

Answer:

\large\boxed{\left(25^{-(3)/(2)}\right)^(1)/(3)=(1)/(5)}

Step-by-step explanation:

\text{Use}\ (a^n)^m=a^(nm)\n\n\left(25^{-(3)/(2)}\right)^(1)/(3)=25^{-(3)/(2)\cdot(1)/(3)}=25^{-(1)/(2)}\n\n\text{Use}\ a^(-n)=(1)/(a^n)\n\n=(1)/(25^(1)/(2))\n\n\text{Use}\ a^(1)/(n)=\sqrt[n]{a}\to a^(1)/(2)=\sqrt[2]{a}=√(a)\n\n=(1)/(√(25))=(1)/(5)

Emma has 16 crackers she eats some could she still have 16 left?

Answers

you can't take away from 16 and still have 16.

Light bulb usually cost $2.00. if the sale is 0.50 of the regular price, what is the sale price

Answers

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Jim & Jesse each had the same amount of money. Jim spent $58 and Jesse spent $37. Afterward, the ratio of Jim's money to Jesse's is 1:4. How much money did each have at first?

Answers

x-\ money\ that\ each\ of\ them \ had\ previously\n\n4(x-58)=x-37\n\n4x-232=x-37\ \ \ | subtract\ x\n\n3x-232=-37\ \ \ | add\ 232\n\n3x=195\ \ \ | divide\ by\ 3\n\nx=65\n\nEach\ of\ them\ had\ 65\$\ at\ the\ beginning.
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