Answer:
200 ft 200
t = -------------------- = ---------- min
(S + T) ft/min S + T
Step-by-step explanation:
Recall that distance = (rate)(time).
The distance traveled by the turtle in t minutes is dt = (T ft/min)(t), and
the distance traveled by the snail in t minutes is ds = (S ft/min)(t). We know that ds + dt must be 200 ft.
Thus,
(S ft/min)(t) + (T ft/min)(t) = 200 ft.
The variable t, representing elapsed time, is common to both terms on the left. Thus,
200 ft 200
t = -------------------- = ---------- min
(S + T) ft/min S + T
Answer:
S+T
Step-by-step explanation:
Answer:
x = 20
Step-by-step explanation:
Turn all the numbers into fractions with the same denominator.
×
Subtract 6.75 from both sides
Then multiply both sides by 8
Then divide both sides by 3 to get x
The height of tree is 32 meter
Solution:
Given that, The sun is at an angle of elevation of 58 degree
A tree casts a shadow 20 meters long on the ground
The sun, tree and shadow forms a right angled triangle
The figure is attached below
ABC is a right angled triangle
AC is the height of tree
AB is the length of shadow
AB = 20 meters
Angle of elevation, angle B = 58 degree
By definition of tan,
In this right angled triangle ABC,
opposite = AC and adjacent = AB
Therefore,
Thus height of tree is 32 meter
Answer:
"The interquartile range (IQR) is a measure of variability, based on dividing a data set into quartiles. ... The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively."
Step-by-step explanation: