Solve for x.
−7.8(x+6.5)=−25.74
Enter your answer, as a decimal, in the box.
Answers
-7.8x - 50.7 = -25.74
-7.8x = -25.74 + 50.7
-7.8x = 24.96
x = 24.96/-7.8
x = -3.2
Related Questions
Identify the equivalent of:6 = 7x – yA. 6 + 7x = yB. -6 + 7x = yC. -6 - 7x = yD. 6 - 7x = y
How you can know a fraction is equivalent to another fraction
A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 14 cm long and 4 cm wide. The diameter of each circle is the width of the rectangle. What is the area of the bookmark? Use 3.14 for π.PLS HELP DUE TOMMORROW.
Simplify -8+6i/4-2i
Answers
Answer:
10200
Step-by-step explanation:
0.12 * 85000 is 10200.
Answers
a = long leg
b = short leg
c = hypotenuse
graph can form a right triangle:
JK: a = 7 - 3 = 4 ; b = 5 - 3 = 2
⇒ 4² + 2² = c² ⇒ 16 + 4 = 20 ; c = √20 = 4.47 or 4.5 units
VW: a = 6 - (-2) = 6 + 2 = 8 ; b = -3 - (+4) = 7
⇒ 8² + 7² = c² ⇒ 64 + 49 = 113 ; c = √113 = 10.63 units
EG: a = 7 - (-2) = 7 + 2 = 9 ; b = 9 - 1 = 8
⇒ 9² + 8² = c² ⇒ 81 + 64 = 145 ; c = √145 = 12.04 units
EG: a = -1 - 6 = 7 ; b = 2 - (-2) = 2 + 2 = 4
⇒ 7² + 4² = c² ⇒ 49 + 16 = 65 ; c = √65 = 8.06 units
Trapezoid: Rectangle and right triangle.
Rectangle = 1 side of the width is the long leg of the right triangle.
a = 8 - 2 = 6 ; b = 12 - 9 = 3
6² + 3² = c² ; 36 + 9 = 45 ; c = √45 = 6.71 units
upper base:CD: 9 - 2 = 7
lower base: BA: 12 - 2 = 10
side: DA: 8 - 2 = 6
side: CB: 6.71
Perimeter = 7 + 10 + 6 + 6.71 = 29.71 units
Since you go up -2 (no negative lengths), and across 4. You can apply the theorem to get:
2^2 + 4^2 = x^2
x = 4.4721
x = 4.5
I won't answer all of these for you, if you need more help just say please.
Answers
The angle of elevation must be 68.202 degrees
Solution:
Given that, 14 foot ladder is used to scale a 13 foot wall
We have to find the angle of elevation must the ladder be situated in order to reach the top of the wall
The figure for this solution is attached below
The ladder, wall and the ground forms a right angled triangle
ABC is a right angled triangle
AB is the height of wall = 13 feet
AC is the length of ladder = 14 feet
We have to find the angle of elevation
Let the angle of elevation be "x"
For right angled triangle ABC, We can use the definition for sine
Here, in figure, opposite = AB and hypotenuse = AC
Thus the angle of elevation must be 68.202 degrees
The angle of elevation the ladder will be situated in order to reach the top of the wall is 68°.
What is a right triangle?
A right triangle has one of its angles as 90 degrees. The angle of elevation can be found using trigonometric ratios.
Therefore, the angle of elevation can be calculated as follows;
The length of the ladder is the hypotenuse.
The opposite side is the height of the wall.
Therefore,
sin ∅ = opposite / hypotenuse
sin ∅ = 13 / 14
∅ = sin⁻¹ 0.92857142857
∅ = 68.2129901712
∅ = 68°
learn more on right triangle here: brainly.com/question/22479729
#SPJ5
Answers
Answer:
x = -1
Step-by-step explanation:
3(x+5)=12
Divide each side by 3
3/3(x+5)=12/3
x+5 = 4
Subtract 5 from each side
x+5-5 = 4-5
x = -1
Answer:
x=-1
Step-by-step explanation:
3(x+5)=12
Step 1: Simplify both sides of the equation.
3(x+5)=12
(3)(x)+(3)(5)=12(Distribute)
3x+15=12
Step 2: Subtract 15 from both sides.
3x+15−15=12−15
3x=−3
Step 3: Divide both sides by 3.
3x
3
=
−3
3
x=−1
Answers
-2x+6y=3
16. Tell whether the lines for each pair of equations are parallel perpendicular or neither
Y=-1/5x+6
-2x+10y= 5
Answers
Answer:
15. The lines are perpendicular.
16. The lines are neither perpendicular nor parallel.
Step-by-step explanation:
15. The given lines are
Y=-3x+7 & -2x+6y=3 or, 6y = 3 + 2x or, .
The slope of the first line is -3 and the slope of the second line is [Comparing with the standard form of equation of straight line y = mx + c, where m is the slope of the straight line].
Two straight lines will said to be perpendicular to each other, if the product of its slopes will be equal to -1.
Since, , the equations are perpendicular with respect to each other.
16. The lines are and -2x + 10y = 5 or, 10y = 5 + 2x or,
.
As per the question number 15, it is clear that these equations are not perpendicular.
Here, the slope of the first one is and the slope of the second one is
.
The values are same with different sign. Hence, these equations are not parallel too.