elastic and gravitational, D
The Objects separated by gravitational force of 360 N, masses 6.25 × 10¹⁴ kg and 7.20 × 10⁵ kg. Applying Newton's law with G = 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² yields distance is 2.79139 km.
We can apply Newton's law of universal gravitation to calculate the distance between the two objects. The formula takes the form:
F = (G ⋅ m₁ ⋅ m₂) / r²
Where:
F represents the force between the two objects
G stands for the gravitational constant (6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²)
m₁ and m₂ denote the masses of the two objects
r indicates the distance between the centers of the two objects
Given that the force F = 360 N, m₁ = 6.25 × 10¹⁴ kg, and m₂ = 7.20 × 10⁵ kg, we can solve for r:
r² = (G ⋅ m₁ ⋅ m₂) / F
r = √((G ⋅ m₁ ⋅ m₂) / F)
Now, substituting the values and solving for r:
r = √(((6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²) ⋅ (6.25 × 10¹⁴ kg) ⋅ (7.20 × 10⁵ kg)) / 360 N)
r ≈ 2791.39 m
Finally, converting the distance from meters to kilometers:
r ≈ 2.79139 km
Consequently, the two objects are approximately 2.79139 kilometers apart.
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Answer:
we have an circuit with two branches in parallel,
* One formed by the switch and three light bulbs
* Another branch formed by a light bulb and the bell
Explanation:
For the construction of the circuit, let us analyze the conditions given, of the 4 light bulbs, only one should remain lit when the dapple is opened, so we must place three light bulbs and the switch in one branch and the other light bulb in the other branch.
For the bell to sound with the abort circuit it must be on the branch where the single bulb is.
Therefore we have an circuit with two branches in parallel,
* One formed by the switch and three light bulbs
* Another branch formed by a light bulb and the bell
Answer:
0.014 kg
Explanation:
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