PHYSICS HIGH SCHOOL

A moving 46.6 kg sled feels a 52.9 N friction force. what is the coefficient of friction

Answers

Answer 1

Answer:

Answer:

The coefficient of friction of the sled is 0.115

Explanation:

It is given that,

Mass of the sled, m = 46.6 kg

Frictional force acting on it, F = 52.9 N

We need to find the coefficient of friction. Frictional force is given by :

$F=\mu mg$

$\mu=(F)/(mg)$

$\mu=(52.9\ N)/(46.6\ kg* 9.8\ m/s^2)$

$\mu = 0.115$

So, the coefficient of friction of the sled is 0.115. Hence, this is the required solution.

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If a wave has a frequency of 2 Hz. what is the period

Answers

The period is the reciprocal of the frequency ... ' 1 ' divided by it.

P = 1/f = 1 / (2 per second) = 1/2 second

Volume of a Cube The volume V of a cube with sides of length x in. is changing with respect to time. At a certain instant of time, the sides of the cube are 7 in. long and increasing at the rate of 0.2 in./s. How fast is the volume of the cube changing (in cu in/s) at that instant of time?

Answers

The volume of the cube is changing at the rate of 29.4 in³/s.

Time derivative:

The rate of change of the sides of the cube is 0.2 in/s, which can be mathematically represented as :

$(dx)/(dt)=0.2 \;in/s$

Now the volume of the cube is given by:

V = x³

If we take the time derivative of the above equation then it gives the rate of change of volume with time, so:

$(dV)/(dt)= (d)/(dt)x^3\n\n (dV)/(dt)= 3x^2(dx)/(dt)$

At the instant x = 7 in, the rate of change of volume will be:

$(dV)/(dt)= 3*7^2*0.2\;in^3/s\n\n(dV)/(dt)=29.4\;in^3/s$

So the volume is changing at 29.4 cubic inches per second.

Learn more about differential equation:

brainly.com/question/25731911?referrer=searchResults

Answer:

Therefore the volume of cube is change at the 29.4 cube in./s at that instant time.

Explanation:

Formula

$(dx^n)/(dx) =nx^(n-1)$

Cube :

The volume of a cube is = $side^3$

The side of length is x in.

Then volume of the cube is (V) = $x^3$

∴ V = $x^3$

Differentiate with respect to t

$(d)/(dt)(V)=(d)/(dt) (x^3)$

$\Rightarrow (dV)/(dt) =3x^2(dx)/(dt)$ ....(1)

Given that the side of the cube is increasing at the rate of 0.2 in/s.

i.e $(dx)/(dt) = 0.2$ in/s.

And the sides of the cube are 7 in i.e x= 7 in

Putting $(dx)/(dt) = 0.2$ and x= 7 in equation (1)

$\therefore (dV)/(dt) =3 * 7^2 * 0.2$ cube in./s

=29.4 cube in./s

Therefore the volume of cube is change at the 29.4 cube in./s at that instant time.

Shear causes horizontal movement along a fault plane in a/n _______ fault. A. reverse B. strike-slip
C. normal
D. irregular

Answers

The answer is B. Strike slip fault. Shearing occurs when plates or blocks of rocks slide past each other in the opposite direction. This occurs at transform plate margins. An example is the San Andreas Fault running through California, USA. Compression occurs at reverse faults and tension at normal faults.

THE ANSWER IS B. STRIKE-SLIP

An observation of the red shift of galaxies suggests that the universe isa.
expanding.
c.
reversing.
b.
contracting.
d.
stagnant.

Answers

An observation of the red shift of galaxies suggests that the universe is expanding. The answer is letter A. . It means that bodies farther away from Earth were moving away faster. The Hubble’s constant is the ratio of distance to redshift equal to 170 kilometers per second per light year of distance.

Answer:

expanding

Explanation:

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b. digestion
c. polymerization
d. exchange of ions between two compounds

Answers

The answer is (b) digestion.
A decomposition reaction is a process in which a single compound breaks into two or multiple elements or compounds. A best example is digestion where a large insoluble food molecules breakdowns into small water-soluble molecules so that they can be absorbed into the watery blood plasma.

the earth is squeezed to the size of the moon, then what will be its effect on the gravity of the earth

Answers

None. Gravity is based on mass not size.

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