A fair coin is tossed 10 times. The coin lands heads up all 10 times.

 

What is the probability that it will land heads up on the next toss?

Answers

Answer 1
Answer: it would be 50% if it is a fair coin


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If arctan(3/5)=K    Tan(k)=?
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What is the aware please

Answers

Answer:

=HI .7.5 units

Step-by-step explanation:

What is , 12-1x0+4÷2???

Answers

Your answer is 14
Order of operations
First you multiply
12-0+4/2
Second you divide
12-0+2
Last you add all terms neglecting the -0
12+2= 14
2 is the answer because if you subtract 12 to 1 it will be 11 and time by 0 and it will be 0 add by 4 and divide it by 2 and it will be 2.

Arrange the systems of equations in order from least to greatest based on the number of solutions for each system.

Answers

Answer:

case 1

3x-7y=9

-4x+5y=1

using a graph tool

the solution is the point (-4,-3)------------------> one solution

case 2

y=6x-2

y=6x-4

two parallel lines

the system has no solution---------------> zero solution

case 3

-5x+y=10

-25x+5y=50

is the same line----------------> infinite solutions

Answer:

work is shown and pictured

What's the lateral area of a right circular cone if the diameter of the base is 4 m and the slant height of the cone is 15m? Round your answer to the nearest whole number. A. 214m2 B. 107m2 C. 94m2 D. 188m2

Answers

We are tasked to solve for the lateral area of a right circular cone given that the base diameter measurement is 4 meters and the slant height measurement is 15 meters. To solve this problem, we need to use the formula below:
Lateral Area = pi*r (√h²+r²)
where r is half of the diameter measurement such as:
radius = r = diameter / 2
r = 4/2
r = 2 meters
Solving for the lateral area, we have it:
Lateral Area = 3.14*2 (√15²+2²)
Lateral Area = 94 m²

The answer is the letter "C".

The correct answer is:

C. 94m2

<3

Find the average speed of a horse that traveled east for 25 km in 4 hours

Answers

Average speed can be viewed as the rate of change in distance with respect to time. A car traveling at an average speed of 25 miles per hour covers an average distance of 25 miles every hour. So for a horse traveling 25 km in 4 hrs has an average speed of 6.25 km/ hr

The direction the horse travels has nothing to do with its speed but...

The horse would be traveling 6.25 km/hr

You simply take the overall travel (25km) and divide it by the total time (4hr)

You get 6.25km  as your answer, meaning that every hour the horse traveled 6.25km every hour.

4 hours later the horse has reached 25km

Differentiate the following functions s=4e^3t-e^-2.5 w.r.t.t

Answers

Answer:

\displaystyle (ds)/(dt) = 12e^(3t)

General Formulas and Concepts:

Algebra I

  • Functions
  • Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle (d)/(dx)[f(x) + g(x)] = (d)/(dx)[f(x)] + (d)/(dx)[g(x)]

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

eˣ Derivative:                                                                                                         \displaystyle (d)/(dx) [e^u]=e^u \cdot u'

Step-by-step explanation:

Step 1: Define

Identify

\displaystyle s = 4e^(3t) - e^(-2.5)

Step 2: Differentiate

  1. eˣ Derivative:                                                                                                 \displaystyle (ds)/(dt) = 4e^(3t) \cdot (d)/(dt)[3t] - (d)/(dt)[e^(-2.5)]
  2. Basic Power Rule:                                                                                         \displaystyle (ds)/(dt) = 4e^(3t) \cdot 3t^(1 - 1) - 0
  3. Simplify:                                                                                                         \displaystyle (ds)/(dt) = 12e^(3t)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

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