MATHEMATICS HIGH SCHOOL

#1. Given the binomials (x - 2), (x - 1), (x + 2), and (x - 4), which one is a factor of f(x) = x3 + 7x2 + 14x + 8? (x - 2) (x - 1) (x + 2) (x - 4) Given the binomials (x + 1), (x + 4), (x - 5), and (x - 2), which one is a factor of f(x) = 3x3 - 12x2 - 4x - 55? (x + 1) (x + 4) (x - 5) (x - 2) #2. What is the f of x over the g of x when f(x) = 6x3 - 19x2 + 16x - 4 and g(x) = x - 2?6x2 - 7x + 2/3x2 - 9x + 8/ 6x2 - 7x + 2 - 8 over the quantity of x minus 2/3x2 - 9x + 8 - 8 over the quantity of x minus 2

#3. What is the f of x over the g of x when f(x) = 6x3 - 19x2 + 16x - 4 and g(x) = x - 2? #4.What is the quotient when -3x3 + 5x + 14 is divided by x - 2? -3x2 - 6x - 7/- 3x2 - x + 12/-3x2 + 6x - 7 + 28 over the quantity of x minus 2/
-3x2 - x + 12 + 28 over the quantity of x minus 2.

#4. What is the quotient when x3 - 5x2 + 2x + 5 is divided by x - 2?

x2 - 3x - 4/ x2 - 7x + 16/x2 - 3x - 4 - 3 over the quantity of x minus 2

x2 - 7x + 16 - 3 over the quantity of x minus 2

Answers

Answer 1
Answer: #1
Factoring the function:
f(x) = x3 + 7x2 + 14x + 8
f(x) = (x + 4) (x + 1) (x + 2)

From the options, (x + 2) is the factor

#2
f(x) / g(x) = (6x3 - 19x2 + 16x - 4) / (x - 2)
This can be solved by factoring the numerator, by synthetic division or using the remainder theorem.

The result is:
6x^2 - 7x + 2 or (x - 2/3)(x - 1/2)
 
#3 same with #2

#4
(x3 - 5x2 + 2x + 5) / (x - 2)
Again, this can be solved by a number of methods, the result is:
x2 -3x - 4 - (3/x-2)
Answer 2
Answer:

#1

Factoring the function:

f(x) = x3 + 7x2 + 14x + 8

f(x) = (x + 4) (x + 1) (x + 2)

From the options, (x + 2) is the factor

#2

f(x) / g(x) = (6x3 - 19x2 + 16x - 4) / (x - 2)

This can be solved by factoring the numerator, by synthetic division or using the remainder theorem.

The result is:

6x^2 - 7x + 2 or (x - 2/3)(x - 1/2)

#3 same with #2

#4

(x3 - 5x2 + 2x + 5) / (x - 2)

Again, this can be solved by a number of methods, the result is:

x2 -3x - 4 - (3/x-2)

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Answers

Ok, the formula to find the area of a regular polygon is...

A = 1/2 nsr

In this equation...

n = number of sides
s= side length
r = apothem (radius of the inscribed circle)

To find the area, we must first find the apothem. The apothem is the radius of the inscribed circle (draw a line from the center of the figure to the center of one of the sides). If you draw the apothem in to the figure, it creates a right triangle with a hypotenuse of 13.07 in and one side length of 5 in (1/2 of the figure's side length). Now we can find the apothem with the formula

a^2 + b^2 = c^2
a^2 = c^2 - b^2
a^2 = 13.07^2 - 5^2
a^2 = 170.8249 - 25
a^2 = 145.8249
a = 12.076

Now we have the value for the apothem and we can plug it into the area formula...

A = 1/2 nsr
(recall that n = number of sides; s= side length; r= apothem)

A = 1/2(8×10×12.076)
A = 40×12.076
A= 483.04 in^2

Rounded to the nearest tenth would be...

483.0 in^2

Solve the following proportion: x+3/2 equal to 7/8

Answers

Step-by-step explanation:

x+ 3/2 = 7/8

3/2 is equivalent to the fraction 12/8

Since the two fractions have common denominators, you can do.

x= 7/8 - 12/8

x=(-5/8)

Hope this helps!!!

Answer:

x = -0.625

Step-by-step explanation:

x+3/2 = 7/8

x + 1.50 = 0.875

x = -0.625

What is greatest to least 1.001,1.1,1.403,1.078

Answers

1.403, 1.1, 1.078, 1.001
From greatest to least, 1.403, 1.1, 1.078, 1.001This can be seen easier by putting zeros at the end of some numbers, but you don't have to. Example: 1.403, 1.100, 1.078, 1.001

How many 25cm diameter cake tins will fit into 600mm by 500mm oven space

Answers

The surface of the oven space is 600 × 500 = 300000 mm^2 = 3000 cm^2;
The surface oh a cake tins is π × (25^2) = 625π ≈ 1963 cm^2;
3000 ÷ 1963 ≈ 1.5;
The anser is 1 cake tins fit into oven space.

The sum of the exterior angles of a pentagon equals 300? True or false

Answers

25 and then add the decimals they have to be aaddd by the two decimals

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Answers

Answer:

a is a pentagon and the angles inside are 108°

b is an octagon with angles of 135°
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